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Zielflug [23.3K]
3 years ago
6

How to delete a brainly account?

Computers and Technology
2 answers:
dmitriy555 [2]3 years ago
7 0

Answer:

Fill the deletion form go to settings and open FAQ ..

Ann [662]3 years ago
3 0

Explanation:

ok go to some mods acc and send private message that u want to delete ur acc

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Mary works for a multimedia firm, and she spends long hours on a desktop computer. Recently, she expired back pain and visited h
Sindrei [870]

To stand as she works.

5 0
2 years ago
Which group of commands all appear on the Standard toolbar?
topjm [15]
I hope this helps

print 
copy 
past 
send 

7 0
3 years ago
Assign decoded_tweet with user_tweet, replacing any occurrence of 'TTYL' with 'talk to you later'. Sample output with input: 'Go
nekit [7.7K]

Answer:

I am going to use the Python programming language to answer this. The source code is given below:

print("Enter your tweet here")

user_tweet = input()

decoded_tweet = user_tweet.replace('TTYL', 'talk to you later')

print("This is the decoded tweet: ")

print(decoded_tweet)

Explanation:

In the program the replace() module was used to replace 'TTYL' with 'talk to you later.'

Attached is the screenshot of the output.

8 0
3 years ago
Read 2 more answers
Suppose that the format for license plates in a certain state is two letters followed by four numbers. (a) How many different pl
Ymorist [56]

Answer:

(a) 6,760,000 plates

(b) 3,407,040 plates

(c) 6,084,000 plates

Explanation:

The very first thing to note about this question is the number of characters involved in the license plate format (6 characters in this case; 2 letters and 4 numbers). The letters come first and then the numbers follow.

There are a total of 26 possible letters (A-Z) and 10 possible numbers (0 - 9) that can be chosen. We can then proceed to the first question;

(a) Here, the total number of possible plates is to be determined. This is done as follows:

Character 1 (Letter): There are 26 possible letters

Character 2 (Letter): There are 26 possible letters

Character 3 (number): There are 10 possible numbers

Character 4 (number): There are 10 possible numbers

Character 5 (number): There are 10 possible numbers

Character 6 (number): There are 10 possible numbers

So, total number of different plates will be obtained by multiplying all the possibilities: 26 × 26 × 10 × 10 × 10 × 10 = 6,760,000 plates

(b) This second part puts a constraint on the usage of the numbers, unlike the question (a), where there was no constraint at all.

Since there is no constraint on the letters, we can write that:

Character 1 (Letter): There are 26 possible letters

Character 2 (Letter): There are 26 possible letters

For the first number as well, we can write:

Character 3 (number): There are 10 possible numbers

However, for the remaining characters, the possibilities will continually reduce by a value of 1, since we can not use a number that has been used before. So,

Character 4 (number): There are 9 possible numbers

Character 5 (number): There are 8 possible numbers

Character 6 (number): There are 7 possible numbers

So, total number of different plates will be: 26 × 26 × 10 × 9 × 8 × 7 = 3,407,040 plates

(c) Here, repetitions are allowed as in questions (a), but there can not be four zeros. This implies that the maximum number of zeros in any plate will be three. Thus, there will be maximum possibilities on all characters until the last one which will be constrained.

Character 1 (Letter): There are 26 possible letters

Character 2 (Letter): There are 26 possible letters

Character 3 (number): There are 10 possible numbers

Character 4 (number): There are 10 possible numbers

Character 5 (number): There are 10 possible numbers

Character 6 (number): There are 9 possible numbers

Total number of plates will therefore be: 26 × 26 × 10 × 10 × 10 × 9 = 6,084,000 plates.

7 0
3 years ago
Write a program that reads numbers from the user until a blank line is entered. Your
ddd [48]

Answer:

nums = []

while True:

   in = input()

   if in:

       nums.append(in)

   else:

       break

if nums:

   avg = sum(nums) / len(nums)

   for i in range(len(nums)):

       if nums[i] == avg:

           print(f"index: {i+1}")

           print(nums[i])

else:

   print(-1)  # if there aren't any values in nums

Explanation:

Assuming that you are coding in Python 3x. The last 'else' statement is an edge case that you might want to consider, I don't know what you want to put there, but I'm just going to leave it as -1.

5 0
2 years ago
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