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3 years ago

Is the function g(x)=-x^2 a translation,compression, stretch, or reflection of the parent function, f(x)=x^2

Mathematics

1 answer:

Shtirlitz [24]3 years ago

7 0

Reflection, a -x with be the opposite of x so it’s a reflection over the x axis

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HELPPPPPPP!!!!!!! Plz

Natalka [10]

The answer is to this question is a)strong positive...

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3 years ago

Lcm of (x-2)(x+3) and 10(x+3)^2

Arte-miy333 [17]

Least common multiple: factor them, then see what they have in common and what is leftover and multiply those expressions:

(x - 2)(x + 3) 10(x + 3)(x + 3)
Common: (x + 3)
Leftover: (x - 2), (10), (x + 3)
Common · Leftover is: (x + 3) · (x - 2) · (10) · (x + 3) = 10(x - 2)(x + 3)²

Answer: LCM is 10(x - 2)(x + 3)²

8 0

3 years ago

Plz show your work. Thx!! <br> 9m=6

grandymaker [24]

So first you would divide the 9 on both sides then 6 divided by 9 would be .6 repeating so m=.6 repeating.

5 0

3 years ago

Use Cramer's Rule to solve the following system: –2x – 6y = –26 5x + 2y = 13

andriy [413]

$\bf \begin{cases}
-2x-6y&=-26\\
\quad 5x+2y&=13
\end{cases}\stackrel{\textit{determinant of the coefficients}}{D=
\begin{bmatrix}
-2&-6\\5&2
\end{bmatrix}}\implies (-4)-(-30)
\\\\\\
D=-4+30\implies \boxed{D=26}\\\\
-------------------------------\\\\$

$\bf x=\cfrac{D_x}{D}\implies x=\cfrac{
\begin{bmatrix}
\boxed{-26}&-6\\\\ \boxed{13}&2
\end{bmatrix}}{D}\implies x=\cfrac{(-52)-(-78)}{26}
\\\\\\
x=\cfrac{-52+78}{26}\implies x=\cfrac{26}{26}\implies \boxed{x=1}\\\\
-------------------------------\\\\
y=\cfrac{D_y}{D}\implies y=\cfrac{
\begin{bmatrix}
-2&\boxed{-26}\\\\ 5&\boxed{13}
\end{bmatrix}}{D}\implies y=\cfrac{(-26)-(-130)}{26}
\\\\\\
y=\cfrac{-26+130}{26}\implies y=\cfrac{104}{26}\implies \boxed{y=4}$

4 0

3 years ago

Find the perimeter of triangle ABC with vertices A(6, 3), B(6, - 2) , and C(- 4, 3) .

anyanavicka [17]

Answer:

26.2 units

Step-by-step explanation:

We are given the points/vertices

A(6, 3),

B(6, - 2) , and

C(- 4, 3)

Step two

Let us find the distances between the given points/vertices

A-B =A(6, 3) to B(6,-2)

d=√((x2-x1)²+(y2-y1)²)

Substitute

d=√((6-6)²+(-2-3)²)

d=√(-2-3)²)

d=√(-5)²)

d=5 units

B-C=B(6, - 2) to C(-4, 3)

d=√((x2-x1)²+(y2-y1)²)

Substitute

d=√((-4-6)²+(3+2)²)

d=√(-10)²+(5)²)

d=√100+25

d=√125

d=11.2 units

C-A=C(-4, 3) to A(6, 3)

d=√((x2-x1)²+(y2-y1)²)

Substitute

d=√((6+4)²+(3-3)²)

d=√(10)²

d=√100

d=10 units

Hence the perimeter is 5+11.2+10

P=26.2 units

4 0

3 years ago