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3 years ago

Which sum or difference is equivalent to the following expression?

Mathematics

1 answer:

vladimir1956 [14]3 years ago

6 0

Answer:

i think it is a

Step-by-step explanation:

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An expression is shown 342 / 8 What is the quotient expressed as a fraction?

tekilochka [14]

/ also means division so the answer is 42.75

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4 years ago

Jane bought a packet of 12 cards for $15.00 <br>What would be the average price of a card?

nignag [31]

12 cards = $15.00

1 card = $15.00 ÷ 12 = $1.25

Answer: $1.25

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3 years ago

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–6(2 + a) = –48 I need help please.

Ksenya-84 [330]

Answer:

a = 6

Step-by-step explanation:

–6(2 + a) = –48

-12 - 6a = -48

-6a = -36

a = -36 ÷ - 6

a = 6

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3 years ago

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Use a surface integral to ﬁnd the surface area of the portion of the sphere xUse a surface integral to ﬁnd the surface area of t

brilliants [131]

Parameterize this surface (call it $S$ ) by

$\vec r(u,v)=\cos u\sin v\,\vec\imath+\sin u\sin v\,\vec\jmath+\cos v\,\vec k$

with $0\le u\le2\pi$ and $0\le v\le\dfrac\pi4$ . The limits on $u$ should be obvious. We find the upper limit for $v$ by solving for $v$ where the sphere and cone intersect:

$\begin{cases}x^2+y^2+z^2=1\\z=\sqrt{x^2+y^2}\end{cases}\implies x^2+y^2=\dfrac12$

$\implies(\cos u\sin v)^2+(\sin u\sin v)^2=\dfrac12$

$\implies\sin^2v=\dfrac12$

$\implies\sin v=\dfrac1{\sqrt2}\implies v=\dfrac\pi4$

Take the normal vector to $S$ to be

$\vec r_u\times\vec r_v=-\cos u\sin^2v\,\vec\imath-\sin u\sin^2v\,\vec\jmath-\cos v\sin v\,\vec k$

(orientation does not matter here)

Then the area of $S$ is

$\displaystyle\iint_S\mathrm dA=\iint_S\|\vec r_u\times\vec r_v\|\,\mathrm du\,\mathrm dv$

$=\displaystyle\int_0^{\pi/4}\int_0^{2\pi}\sin v\,\mathrm du\,\mathrm dv$

$=\displaystyle2\pi\int_0^{\pi/4}\sin v\,\mathrm dv=\boxed{(2-\sqrt2)\pi}$

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3 years ago

Estimate the sum of 703 and 620

rosijanka [135]

I think 1323 is the sum

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4 years ago

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