Answer:
Normal daughters and Hemophiliac son
Explanation:
Females exhibit hemophilia and colorblindness in homozygous genotype only.
The genotype of hemophiliac woman= X^hX^h
The genotype of colorblind man= X^cY
A cross between X^hX^h and X^cY would produce progeny in the following phenotype ratio= 1 Normal but carrier daughters:1 Hemophiliac son
Answer:
In a cross between two black-haired guinea pigs, 20 offspring are born. If both parents were heterozygous, probability would predict that approximately 1 out of 20 offspring would have brown hair
Explanation:
The two parents crossed were heterozygous dominant black coat color, after crossing 75% gives dominant black color coat while 25% gives only brown coat color homozygous
False its called cell division not splitting it is splitting but the correct term is cell division
