Answer:
<u>It</u><u> </u><u>is</u><u> </u><u>5</u><u>9</u><u>,</u><u>2</u><u>7</u><u>5</u><u>.</u><u>7</u><u>4</u><u> </u><u>grams</u>
Step-by-step explanation:
• Molecular mass of carbon dioxide

[ molar masses: C = 12 g, O = 16 g ]
• From avogadro's number, it says 1 mole contains 6.02 × 10^23 molecules or atoms.
But 1 mole is equivalent to its molar mass in terms of weight, therefore;
