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Yanka [14]
3 years ago
7

(3) Lines that forms straight angles​

Mathematics
1 answer:
Nataly [62]3 years ago
8 0
They are called supplementary angles.
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The function g(x) is the inverse of the function f (x) = (x + 1)2 + 2, when x < -1
kondaur [170]

9514 1404 393

Answer:

  g(x) = -√(x -2) -1

Step-by-step explanation:

We note the domain of f(x) is x ≤ -1. The is the range of the function g(x).

The inverse function is the solution to ...

  x = f(y)

  x = (y +1)² +2

  x -2 = (y +1)²

  -√(x -2) = y +1 . . . . . . . we are interested only in the negative values

  y = -√(x -2) -1

The inverse function is ...

  g(x) = -√(x -2) -1

3 0
3 years ago
You compare the number of words per sentence in a sports magazine to the number of words per sentence in a fashion magazine. The
goldenfox [79]

Answer:

answer is b

Step-by-step explanation:

8 0
3 years ago
Find the number of permutations in the word fission <br> 1020<br> 1500<br> 1260<br> 2400
irina [24]
There are 7 letters in fission, which we'll use as a factorial in the numerator. Of those 7 letters, there are two I's and two S's. To account for these repeating letters, we'll use the factorials of how many times the letters repeat and plug them into the denominator.

The factorial of 7 should be your numerator, and two factorials of 2 should be your denominator:

\frac{7!}{2! \times 2!} =  \frac{5040}{2 \times 2} =  \frac{5040}{4} =  1260

There are 1260 different permutations of the word fission.
5 0
3 years ago
⊙O and ⊙P are given with centers (−2, 7) and (12, −1) and radii of lengths 5 and 12, respectively. Using similarity transformati
goldenfox [79]

Answer:

Whereby circle \bigodotP can be obtained from circle \bigodotO by applying the transformations of a translation of T₍₁₄, ₋₈₎ followed by a dilation by a scale factor of 2.4, \bigodotO is similar to \bigodotP

Step-by-step explanation:

The given center of the circle \bigodotO = (-2, 7)

The radius of \bigodotO, r₁ = 5

The given center of the circle \bigodotP = (12, -1)

The radius of \bigodotP, r₂ = 12

The similarity transformation to prove that \bigodotO and \bigodotP are similar are;

a) Move circle \bigodotO 14 units to the right and 8 units down to the point (12, -1)

b) Apply a scale of S.F. = r₂/r₁ = 12/5 = 2.4

Therefore, the radius of circle \bigodotO is increased by 2.4

We then obtain \bigodotO' with center at (12, -1) and radius r₃ = 2.4×5 = 12 which has the same center and radius as circle \bigodotP

∴ Circle \bigodotP can be obtained from circle \bigodotO by applying similarity transformation of translation of T₍₁₄, ₋₈₎ followed by a dilation by a scale factor of 2.4, \bigodotO is similar to \bigodotP.

7 0
3 years ago
What is 10/3 as a whole number
Vladimir [108]

Answer:

Three and one third

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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