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Soloha48 [4]
3 years ago
10

The length of a rectangle is twice its width. The perimeter is 60 feet, Find the area.

Mathematics
2 answers:
belka [17]3 years ago
8 0
  • Let the width of the rectangle be <em>x feet</em>.
  • Then, the length of the rectangle = <em>2</em><em>x</em><em> </em><em>feet.</em>
  • Perimeter = <em>6</em><em>0</em><em> </em><em>feet </em><em>(</em><em>given)</em>
  • Therefore, by the problem

2(x+2x) = 60

or, 2x+4x = 60

or, 6x = 60

or, x = 10

  • The width of the rectangle is <em>10 feet</em> and the length of the rectangle is <em>(2×10) feet, i.e., 20 feet.</em>
  • Therefore, the area of the rectangle

= length × width

= (10×20) square feet

= 200 square feet

<h3>The area of the rectangle is <em>2</em><em>0</em><em>0</em><em> </em><em>square </em><em>feet.</em></h3>
irina [24]3 years ago
6 0

Answer:

The area is 200 ft^2

Step-by-step explanation:

The perimeter is 60 and the windth is twice larger, so the lenght is 10 ft and the width is 20 ft.

10x20= 200ft^2

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