Question

The length of a rectangle is twice its width. The perimeter is 60 feet, Find the area.

Answer 1

• Let the width of the rectangle be x feet.
• Then, the length of the rectangle = 2x feet.
• Perimeter = 60 feet (given)
• Therefore, by the problem

2(x+2x) = 60

or, 2x+4x = 60

or, 6x = 60

or, x = 10

• The width of the rectangle is 10 feet and the length of the rectangle is (2×10) feet, i.e., 20 feet.
• Therefore, the area of the rectangle

= length × width

= (10×20) square feet

= 200 square feet

The area of the rectangle is 200 square feet.

Answer 2

Answer:

The area is 200 ft^2

Step-by-step explanation:

The perimeter is 60 and the windth is twice larger, so the lenght is 10 ft and the width is 20 ft.

10x20= 200ft^2