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REY [17]
3 years ago
14

slader How many partitions of the set {1, 2, 3, . . . , 100} are there such that there are exactly three parts and elements 1, 2

and 3 are in different parts?
Mathematics
1 answer:
My name is Ann [436]3 years ago
7 0

Answer:

3^{97} partitions.

Step-by-step explanation:

As we know if we have x number of elements we can arrange them in x! ways.

here we have 100 elements so we can arrange them in 100! ways.

Now if we have exactly three parts and 1,2 and 3 are in different parts then let consider 1 goes to part 1, 2 goes to part 2, and 3 goes to part 3. For the remaining 97 elements,  we have three options for each element, thus we can arrange the remaining 97 elements in 3^{97} ways/partitions.

each of these partition will contain only three elements.

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What is the answer to all of them?
melisa1 [442]
The answers are
x=5
n=3
y=4
k=-80
3 0
3 years ago
Anyone help me, please I need help<br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7Bx%20-%205%7D%20%20%3D%20%208%20%5Csqrt%5B%5
Ilya [14]

Answer:

No Real Solutions.

Step-by-step explanation:

√(x-5)=8√(x-2)

Square on both sides,

(√(x-5))^2=(8√(x-2))^2

or,(x-5)=64(x-2)

or,x-5=64x-128

or,-5+128=64x-x

or,123/63=x

Therefore, x=41/21

If you plug x=41/21 in √(x-5)=8√(x-2) you do not get equals, so the problem has no real solutions.

7 0
3 years ago
How do you simplify <img src="https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B2%7D%20%2B%5Csqrt%7B6%7D%20%7D%7B%5Csqrt%7B8%7D%20%2B%
blondinia [14]

The trick is to exploit the difference of squares formula,

a^2-b^2=(a-b)(a+b)

Set a = √8 and b = √6, so that a + b is the expression in the denominator. Multiply by its conjugate a - b:

(\sqrt8+\sqrt6)(\sqrt8-\sqrt6)=(\sqrt8)^2-(\sqrt6)^2=8-6=2

Whatever you do to the denominator, you have to do to the numerator too. So

\dfrac{\sqrt2+\sqrt6}{\sqrt8+\sqrt6}=\dfrac{(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)}{(\sqrt8+\sqrt6)(\sqrt8-\sqrt6)}=\dfrac{(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)}2

Expand the numerator:

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=\sqrt{2\cdot8}+\sqrt{6\cdot8}-\sqrt{2\cdot6}-(\sqrt6)^2

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=\sqrt{16}+\sqrt{48}-\sqrt{12}-6

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=4+\sqrt{48}-\sqrt{12}-6

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=-2+\sqrt{12}(\sqrt4-1)

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=-2+\sqrt{12}(2-1)

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6}=-2-\sqrt{12}

So we have

\dfrac{\sqrt2+\sqrt6}{\sqrt8+\sqrt6}=-\dfrac{2+\sqrt{12}}2

But √12 = √(3•4) = 2√3, so

\dfrac{\sqrt2+\sqrt6}{\sqrt8+\sqrt6}=-\dfrac{2+2\sqrt3}2=\boxed{-1-\sqrt3}

7 0
3 years ago
A French restaurant used 848,540 ounces of cream last year. This year, due to a menu update, it used 40% less. How much cream di
Vsevolod [243]

Answer:

339416

Step-by-step explanation:

848,540 * 40/100 = 339416

4 0
3 years ago
I used 1/3 of a bottle of wax to wax 3/4 of a car. How many cars can I wax with one bottle? Please helppp
blsea [12.9K]

Answer:

2.25 cars are waxed with one bottle

Step-by-step explanation:

1/3 * 3 = 1

3/4 * 3 = 9/4

9/4 = 2.25

4 0
3 years ago
Read 2 more answers
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