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REY [17]
3 years ago
14

slader How many partitions of the set {1, 2, 3, . . . , 100} are there such that there are exactly three parts and elements 1, 2

and 3 are in different parts?
Mathematics
1 answer:
My name is Ann [436]3 years ago
7 0

Answer:

3^{97} partitions.

Step-by-step explanation:

As we know if we have x number of elements we can arrange them in x! ways.

here we have 100 elements so we can arrange them in 100! ways.

Now if we have exactly three parts and 1,2 and 3 are in different parts then let consider 1 goes to part 1, 2 goes to part 2, and 3 goes to part 3. For the remaining 97 elements,  we have three options for each element, thus we can arrange the remaining 97 elements in 3^{97} ways/partitions.

each of these partition will contain only three elements.

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Mariana solved a linear equation and found that it had an infinite number of solutions. Which could have been the final line of
Fofino [41]

Answer:

0=0

Step-by-step explanation:

Well, the linear equation can be expressed as y=ax+b in the solution of linear equations, there 3 main cases can be concluded as final lines. 1st case - the linear equation has no solution (for example, 0*x=5 has no solutions). 2nd case - the linear equation has one solution (for example 4*x=3 where the only one solution is x=0.75) and the 3rd case - the linear equation has infinite number of solutions (for example 0*x=0). So, in our case (3rd case) the last line can be concluded as 0=0.  

4 0
3 years ago
60.2 rounded to the nearest hundredth
Anna11 [10]
It’s gunna be 60.2 I believe
6 0
3 years ago
The diameter of a circle measures 32 mm. What is the circumference of the circle? Use 3.14 for , and do not round your answer. B
mart [117]

Answer:

100.48 ft

Step-by-step explanation:

8 0
2 years ago
Which of the following describes the diagonals of a square?
Feliz [49]

Answer:

ALL OF THE ANSWERS ARE CORRECT .

HOPE IT HELP YOU.

5 0
3 years ago
HI PLEASE HELP ME WITH MY CALCULUS 1 HW? I AM REALLY STUCK. I need help with parts d,e,g.
asambeis [7]

(d) The particle moves in the positive direction when its velocity has a positive sign. You know the particle is at rest when t=0 and t=3, and because the velocity function is continuous, you need only check the sign of v(t) for values on the intervals (0, 3) and (3, 6).

We have, for instance v(1)\approx-0.91 and v(4)\approx0.91>0, which means the particle is moving the positive direction for 3, or the interval (3, 6).

(e) The total distance traveled is obtained by integrating the absolute value of the velocity function over the given interval:

\displaystyle\int_0^6|v(t)|\,\mathrm dt=\int_0^3-v(t)\,\mathrm dt+\int_3^6v(t)\,\mathrm dt

which follows from the definition of absolute value. In particular, if x is negative, then |x|=-x.

The total distance traveled is then 4 ft.

(g) Acceleration is the rate of change of velocity, so a(t) is the derivative of v(t):

a(t)=v'(t)=-\dfrac{\pi^2}9\cos\left(\dfrac{\pi t}3\right)

Compute the acceleration at t=4 seconds:

a(t)=\dfrac{\pi^2}{18}\dfrac{\rm ft}{\mathrm s^2}

(In case you need to know, for part (i), the particle is speeding up when the acceleration is positive. So this is done the same way as part (d).)

6 0
3 years ago
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