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Dovator [93]
2 years ago
7

Can someone explain this to me

Mathematics
1 answer:
inysia [295]2 years ago
7 0

Let me start from taking equation in two dimensional plane

A x + B y= C

P x +Q y  = R

<u>For one Solution   </u>

⇒The two lines are intersecting at a single point.

\frac{A}{P} \neq \frac {B}{Q}\neq \frac{C}{R}

For example, x + y =4 and x - y=2

<u>For infinite solution</u>

⇒The two lines are Coincident.i.e one lies above the other.

For that,

\frac{A}{P} = \frac{B}{Q}=\frac{C}{R}

For example, x + y =3,and 3 x + 3 y =9

<u>For No solution</u>

It means the two lines are parallel i.e they will never intersect.

\frac{A}{P}=\frac{B}{Q}\neq\frac{C}{R}

For example, x + y = 11 and 7 x + 7 y = 11

Now consider equation in three dimensional system

Ax +By+Cz=P

Lx +My+Nz=Q

Tx +Uy+Vz=R

You can solve this system of equation by cramers rule or by any other method.

For example taking Cramers rule into consideration

x =\frac{D_{1}}{D}, y=\frac{D_{2}}{D},  z=\frac{D_{3}}{D}

For unique Solution or one solution

D ≠ 0

These three lines will intersect at a single point in a three dimensional plane.

x,y,z should have real number as a solution.for example, x=5,y=3,z=4 can be the solution of system of linear equation in three variable satisfying all the equation.

x+y+z=12

2x +y+z =17

x+2y +3z=23

For infinite Solution

These three lines will be Coincident, i.e lies above one another.

I.e,

D=D_{1}=D_{2} =D_{3}=0

for example

x +y+z =6

2x +2y +2z=12

3x+ 3y+3z=18 has infinitely many solution.

For no solution

if D=0 and either of D_{1}, or D_{2} orD_{3} is non zero ,it has no solution.

The three lines will be parallel to each other.

For example

x + y+z=3

2x +2y+2z =5

4x + 4y + 4z =17

It has no solution.






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Amy(A): D + 12
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SumOfAll(S)=208 : Total points / sum of all three friends

(D+12)+D+2D=208
D+12+3D=208 - transpose 12 to the right side
4D=208-12 
4D = 196   - divide both sides by 4
D=49
Therefore, Doug scored 49

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The rule for the sequence is S(n) = 2S(n-1) - S(n-2)

Alternative form: S(n) = S(n-1) + 3

Step-by-step explanation:

In this problem, we know the first two terms of the sequence:

S(1) = 2

S(2) = 5

We are told that each term after the second is created by subtracting the term before the previous term from twice the previous term. In other words, if we call:

S(n) the current term

S(n-1) the previous term

S(n-2) the term before the previous term

This statement translates into the following sequence:

S(n) = 2S(n-1) - S(n-2)

Because we are subtracting the term before the previous term, S(n-2), from twice the previous term, 2S(n-1).

We can apply now the rule to find the first few terms of the sequence after S(1) and S(2):

S(3) = 2S(2) - S(1) = 2(5)-2=10-2 = 8

S(4) = 2S(3) - S(2) = 2(8)-5=16-5 = 11

S(5) = 2S(4) - S(3) = 2(11)-8=22-8 = 14

We notice also that each term of the sequence is just equal to the previous term plus 3, so the sequence can also be written as

S(n) = S(n-1) + 3

Learn more about sequences:

brainly.com/question/1522572

brainly.com/question/3280369

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