I need help with this problem

Mathematics

1 answer:

katrin [286]2 years ago

5 0

9514 1404 393

Answer:

(d) y = -2x +8

Step-by-step explanation:

The parallel line will have the same x-coefficient, eliminating choices B and C. If it goes through point (4, 0), then (x, y) = (4, 0) will satisfy the equation.

A: 0 = -2(4) +4 = -4 . . . . . not true

D: 0 = -2(4) +8 . . . . . . . . true

The equation you're looking for is ...

y = -2x +8

<em>Additional comment</em>

Since you know the slope is -2 and a point on the line is (4, 0), you can use the point-slope form of the equation for a line as a starting point.

y -k = m(x -h) . . . . . . line with slope m through point (h, k)

For m = -2, and (h, k) = (4, 0), the equation becomes ...

y -0 = -2(x -4)

Simplified to slope-intercept form, this is ...

y = -2x +8

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In 1982 Abby’s mother scored at the 93rd percentile in the math SAT exam. In 1982 the mean score was 503 and the variance of the

oksian1 [2.3K]

Answer:

The percentle for Abby's score was the 89.62nd percentile.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation(which is the square root of the variance) $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Abby's mom score:

93rd percentile in the math SAT exam. In 1982 the mean score was 503 and the variance of the scores was 9604.

93rd percentile. X when Z has a pvalue of 0.93. So X when Z = 1.476.

$\mu = 503, \sigma = \sqrt{9604} = 98$