Answer:
The magnitude of the electric force between these two objects
will be: 181.274 N.
i.e. F
N
Step-by-step explanation:
As
Two object accumulated a charge of 4.5 μC and another a charge of 2.8 μC.
so
q₁ = 4.5 μC = 4.5 × 10⁻⁶ C
q₂ = 2.8 μC = 2.8 × 10⁻⁶ C
separated distance = d = 2.5 cm
Calculating the magnitude of the force between two charged objects using the formula:


∵ 
∵ 


∵ 
∵ 

F
N
Therefore, the magnitude of the electric force between these two objects will be: 181.274 N.
i.e. F
N
Answer:
y = 5 and x = -3
Step-by-step explanation:
Given,
y = x + 8 ...............( equation 1 )
x + y = 2 ...............( equation 2 )
Now, by substituting the value of y in equation 2, we get;
⇒ x + x + 8 = 2
⇒ x = -3
and now, by substituting the value of x in equation 1, we get;
⇒ y = -3 + 8
⇒ y = 5
Answer:
I also got 27.44 mg.
Step-by-step explanation:
Use the function given to you:
A(t)=le^rt
l: Initial Amount (50)
r: Rate (-.1) (Negative because the medicine is exiting the bloodstream at 10% per hour
t: 6 (the specific time value you are evaluating the function at.
A(6)=50e^-.1(6)=27.44
You will need $4270 more
(9500+1500+1870)-(6100+2500)
12870-8600
4270