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velikii [3]
3 years ago
12

What is the solution to this 2x+1+x=3(x-2)+7

Mathematics
1 answer:
podryga [215]3 years ago
8 0

Answer:

infinite solutions

x is all real numbers

Step-by-step explanation:

2x+1+x=3(x-2)+7

Distribute

2x+1 +x = 3x -6+7

Combine like terms

3x+1 = 3x+1

Subtract 3x from each side

3x-3x+1 = 3x-3x+1

1=1

This is always true, so it doesn't matter what value we put in for x

X is all real numbers

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Can you help? Having a hard time figuring this out. Thanks
Dmitrij [34]

Answer:

3a) The value of  x = 56

3b) The measure of ∠ H T M = 90°

3c) The radius of the circle = 53

Step-by-step explanation:

3a) ∵ A F is a tangent to the circle O at point F

∵ Secant AH intersects circle O at point T

∴ (A F)² = (A T)(A H)

∴ 7( x + 7) = (21)² ⇒ ÷ 7

∴ x + 7 = 63

∴ x = 63 - 7 = 56

3b) ∵ HM is a diameter

∴ The measure of the arc HM = 180° ⇒ semi-circle

∵ ∠ H T M is inscribed angle subtended by the arc HM

∴ m ∠ H T M = half the measure of arc HM

∴ m ∠ H T M = 180° ÷ 2 = 90°

3c) ∵ Δ H T M is a right angle triangle at T

∴ (H M)² = (M T)² + (H T)² ⇒ Pythagorean theorem

∴ (H M)² = (90)² + (56)²

∴ (H M)² = 11236

∴ HM = \sqrt{11236} = 106

∴ OM = 106 ÷ 2 = 53

∵ OM is the radius of the circle O

∴ The radius  = 53

4 0
3 years ago
When dropped, a super ball will bounce back to 80% of its peak height,continuing on in this way for each bounce.
Liono4ka [1.6K]

An expression for the height of the nth bounce is 0.80X^N = Height.

<h3><u>Equations</u></h3>

Since when dropped, a super ball will bounce back to 80% of its peak height, continuing on in this way for each bounce, to determine an expression for the height of the nth bounce the following calculation must be performed:

  • X = Initial value
  • 80% = 0.80
  • N = Number of times the ball bounces
  • 0.80X^N = Height

Therefore, an expression for the height of the nth bounce is 0.80X^N = Height.

Learn more about equations in brainly.com/question/2263981

3 0
2 years ago
Why does the shape of the distribution of the weights of russet potatoes tend to be symmetrical?
Sergio [31]

Answer:

Mean ≈ Median

6 0
3 years ago
Read 2 more answers
A box contains 3 green marbles, 5 blue marbles, and 7 red marbles. Three marbles are selected at random from the box, one at a t
USPshnik [31]

Answer:

The probability is  P(K)  =   \frac{ 28 }{195}

Step-by-step explanation:

From the question we are told that

   The number of green marbles is  n_g  =  3

    The number of red marbles is  n_b  =  5

     The number of red marbles is  n_r  =  7

Generally the total number of marbles is mathematically represented as

       n_t  =  n_r  +  n_g + n_ b

        n_t  =  7 +  3 + 5

         n_t  = 5

Generally total number of marbles that are not red is  

     n_k  =  n_g +  n_ b

=>  n_k  =   3 +   5

=>  n_k  =  8

The probability of the first ball not being red is mathematically represented as  

      P(r') =  \frac{n_k}{n_t}

=>  P(r') =  \frac{ 8}{15}

The probability of the second ball not being red is mathematically represented as

      P(r'') =  \frac{n_k - 1}{n_t -1}

=>  P(r'') =  \frac{ 8 -1 }{15-1} (the subtraction is because the marbles where selected without replacement  )

=>  P(r'') =  \frac{ 7 }{14}

The probability that the first two balls  is  not red is mathematically represented as

    P(R) =  P(r') *  P(r'')

=>  P(R) =  \frac{ 8}{15} *   \frac{ 7 }{14}

=>  P(R) =  \frac{ 8 }{30}

The probability of the third ball being red is mathematically represented as

   P(r) =  \frac{n_r}{ n_t -2} (the subtraction is because the marbles where selected without replacement  )

     P(r) =  \frac{7}{ 15 -2}

=>    P(r) =  \frac{7}{ 13}

Generally the probability of the first two marble not being red and the third marble being red is mathematically represented as

        P(K)  =  P(R) * P(r)

         P(K)  =   \frac{ 8 }{30} * \frac{7}{ 13}

=>      P(K)  =   \frac{ 28 }{195}

6 0
3 years ago
What is 7/9 - 5/18 lowest common denominator
NISA [10]
7/9 = 14/18
14-5=9
9/18=1/2
6 0
3 years ago
Read 2 more answers
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