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kirill115 [55]
3 years ago
9

How would covering the sandy banks of the pond affect the turtles’ life cycle?

Chemistry
1 answer:
Stells [14]3 years ago
7 0

Answer:

my answer is i dont know  to be honest this is hard and i have the same question to thanks

Explanation:

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A solution is prepared from 26.7 g of an unknown compound and 116.2 g acetone, C3H6O, at 313 K. At this temperature the vapor pr
Cloud [144]

Answer:

The molecular weight of the unknown compound is 267.7 g/mol

Explanation:

Lowering vapor pressure → Colligative property where the vapor pressure of solution is lower than vapor pressure of pure solvent

ΔP = P° . Xm

0.526 atm - 0.501 atm = 0.025atm

0.025 atm = 0.526 atm . Xm

Xm = 0.025 atm / 0.526 atm → 0.0475 (mole fraction)

Mole fraction = Moles of solute / Total moles (solute + solvent)

0.0475 = Moles of solute / Moles of solute + Moles of solvent

We determine the moles of solvent → 116.2 g . 1mol / 58 g = 2 moles

0.0475 = Moles of solute / Moles of solute + 2

0.0475 moles of solute + 0.095 = Moles of solute

0.095 = Moles of solute - 0.0475 moles of solute

0.095 / 0.9525 = Moles of solute → 0.0997 moles

Molas mass = g/mol → 26.7 g / 0.0997 mol = 267.7 g/mol

4 0
3 years ago
Object a has a mass of 12 grams and a density of 3 grams centimeters cubed object B has a mass of 12 grams and a density of 5 gr
gregori [183]
Your answer is going to be A
8 0
4 years ago
One of the steps in the commercial process for converting ammonia to nitric acid is the conversion of NH3 to NO: 4NH3 (g) 5O2 (g
madreJ [45]

Answer:

O2 is the limiting reactant.

Explanation:

Step 1: Data given

Mass of NH3 = 2.00 grams

Mass of O2 = 2.50 grams

Molar mass NH3 = 17.03 g/mol

Molar mass O2 = 32 g/mol

Step 2: The balanced equation

4NH3(g) +  5O2 (g) → 4NO(g) +  6H2O (g)

Step 3: calculate moles NH3

Moles NH3 = mass NH3 / molar mass NH3

Moles NH3 = 2.00 grams / 17.03 g/mol

Moles NH3 = 0.117 moles

Step 4: Calculate moles O2

Moles O2 = mass / molar mass O2

Moles O2 = 2.50 grams / 32 g/mol

Moles O2 = 0.0781 moles

Step 5: Calculate the limiting reactant

For 4 moles NH3 we need 5 moles O2 to produce 4 moles NO and 6 moles H2O

O2 is the limiting reactant. It will completely be consumed. (0.0781 moles). NH3 is in excess. There will react 4/5 * 0.0781 moles =  0.0625 moles

There will remain 0.117 - 0.0625 = 0.0545 moles NH3

O2 is the limiting reactant.

8 0
4 years ago
Draw a complete structural formula and a condensed structural formula for(a) three compounds of formula C3H8O (b) five compounds
Marat540 [252]

Answer:

Explanation:

A. Attached is a page which contain the structural formula of the three compounds of C3H80.

Condensed structural formula of C3H8O:

Propan-1-ol: CH3CH2CH2OH

Propan-2-ol: CH3CH(OH)CH3

Methoxy methane: CH3OCH2CH3

B. Attached are is a page which contain the structural formula of the three compounds of C3H60.

Condensed structural formula of C3H6O:

Propanal: CH3CH2CHO

Propanone: CH3COCH3

Cyclopropanol: (C3H5)OH

2-propen-1-ol: CH2CHCH2OH

1-propenol: CH3CHCHOH

4 0
4 years ago
what is the change in the velocity of the biker below as he travels from point b to point c ? ..... What is his acceleration fro
Furkat [3]

The change in the velocity = 4 m/s

Acceleration = 4 m/s²

<h3>Further explanation</h3>

Given

vo = initial velocity = 4 m/s

vf = final velocity = 8 m/s

t = 1 s

Required

The change in the velocity

Acceleration

Solution

the change in velocity =

\tt vf-vo=8-4=4~m/s

Acceleration = ratio of a change in velocity and the time

\tt a=\dfrac{\Delta v}{t}= \dfrac{vf-vo}{t}

Input the value :

\tt a=\dfrac{4~m/s}{1~s}=4~m/s^2

7 0
3 years ago
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