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Tom [10]
3 years ago
12

I need the answers any help can be good

Chemistry
1 answer:
aleksandrvk [35]3 years ago
8 0
2.a)R b)R c)L d)L e)R f)L g)L
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Please help me I would really appreciate it
denis-greek [22]
The number of students is your independent variable
6 0
3 years ago
KClO3 (s) KCl (s) + 02 (g)​<br><br><br>How do you balance this equation
Vitek1552 [10]

Answer:

2KCl(s) + 6O3O2

Explanation:

I think it's correct

7 0
2 years ago
Use the particle theory to describe each of the three states of matter.
Anna007 [38]
Matter can exist in one of three main states: solid, liquid, or gas. Solid matter is composed of tightly packed particles. A solid will retain its shape; the particles are not free to move around. ... Gaseous matter is composed of particles packed so loosely that it has neither a defined shape nor a defined volume.
7 0
2 years ago
If heat transfers from the system (solute) to the surroundings (solvent), then AH is
balu736 [363]

Answer:

B) exothermic.

Explanation:

Hello!

In this case, we need to keep in mind that exothermic reactions release heat, so they increase the temperature as the final energy is less than the initial energy; in contrast, endothermic reactions absorb heat, so they decrease the temperature as the final energy is greater than the initial energy.

In such a way, when a dissolution process shows off a negative enthalpy of dissolution, we infer it is an exothermic process due to the aforementioned; therefore, the answer is:

B) exothermic .

Best regards!

3 0
3 years ago
Which gas will effuse at the rate closest At a particular pressure and temperature, nitrogen gas effuses at the rate of 79mLs. U
Contact [7]

Answer : The rate of effusion of sulfur dioxide gas is 52 mL/s.

Solution :

According to the Graham's law, the rate of effusion of gas is inversely proportional to the square root of the molar mass of gas.

R\propto \sqrt{\frac{1}{M}}

or,

(\frac{R_1}{R_2})=\sqrt{\frac{M_2}{M_1}}       ..........(1)

where,

R_1 = rate of effusion of nitrogen gas = 79mL/s

R_2 = rate of effusion of sulfur dioxide gas = ?

M_1 = molar mass of nitrogen gas  = 28 g/mole

M_2 = molar mass of sulfur dioxide gas = 64 g/mole

Now put all the given values in the above formula 1, we get:

(\frac{79mL/s}{R_2})=\sqrt{\frac{64g/mole}{28g/mole}}

R_2=52mL/s

Therefore, the rate of effusion of sulfur dioxide gas is 52 mL/s.

4 0
3 years ago
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