I need the answers any help can be good

In your body, carbon dioxide, CO2, dissolves in the blood to form carbonic acid, H2CO3 as follows:

Answer:

STOP USING THIS SIGHT STOP

Explanation:

not good for ua quart of stain covers 100 square ft how many quarts should you buy to stain the ramp assume you dont have to stain the bottem its lenth is 7 ft 1 side is 35ft the other 35 1/6 ft and the hight is 35 ft

a quart of stain covers 100 square ft how many quarts should you buy to stain the ramp assume you dont have to stain the bottem its lenth is 7 ft 1 side is 35ft the other 35 1/6 ft and the hight is 35 ft

3 0

3 years ago

1. Which is an example of covalent bonding?

iren [92.7K]

join me for answers

any one free out

sin theta equals to cos theta then the value of sin 2 theta

8 0

3 years ago

15. How many grams are equal to 0.11 mole of copper(1) chromate, Cu2(CrO4)? with work please

aleksandr82 [10.1K]

Answer:

26.8g

Explanation:

The formula of the compound given is:

Cu₂CrO₄

Given:

Number of moles = 0.11

To find the mass, we use the expression below:

Mass = number of moles x molar mass

Molar mass of Cu₂CrO₄ = 2(63.6) + 52 + 4(16) = 243.2g/mol

Now insert the parameters and solve;

Mass = 0.11 x 243.2 = 26.8g

7 0

3 years ago

Calculate the number of molecules in 0.54 grams of Ca(NO3)2

Volgvan

Explanation:

We have to find the number of molecules that are present in 0.54 g of Ca(NO₃)₂.

First we have to convert the mass of our sample into moles of Ca(NO₃)₂. We will use the molar mass of Ca(NO₃)₂ to do that.

molar mass of Ca = 40.08 g/mol

molar mass of N = 14.01 g/mol

molar mass of O = 16.00 g/mol

molar mass of Ca(NO₃)₂ = 1 * 40.08 g/mol + 2 * 14.01 g/mol + 6 * 16.00 g/mol

molar mass of Ca(NO₃)₂ = 164.10 g/mol

mass of Ca(NO₃)₂ = 0.54 g

moles of Ca(NO₃)₂ = 0.54 g * 1 mol/(164.10 g)

moles of Ca(NO₃)₂ = 0.00329 moles

According to Avogadro's number there are 6.022 *10^23 molecules in 1 mol of molecules. We can use that relationship to find the number of molecules that are present in our sample.

6.022 *10^23 molecules = 1 mol

molecules of Ca(NO₃)₂ = 0.00329 moles * 6.022 *10^23 molecules/(1 mol)

molecules of Ca(NO₃)₂ = 2.0 * 10^21 molecules

Answer: there are 2.0 * 10^21 molecules of Ca(NO₃)₂ in 0.54 g of it.

5 0

1 year ago

Suppose that a newly discovered element called centium has 3 isotopes that occure in nature. These are centium -200, centium -20

vodomira [7]

Answer:

The answer to your question is 203.8 g

Explanation:

Data

Average atomic mass = ?

Centium-200

Centium-203

Centium-209

Equal amounts

Process

1.- Determine the abundance of each isotope.

If they are in equal amounts in nature, just divide 100 by 3

100/3 = 33.33 % or 0.333

2.- Determine the Average atomic mass

Average atomic mass = Atomic mass 1 x abundance + Atomic mass 2 x

abundance + Atomic mass 3 x abundance

- Substitution

Average atomic mass = 200 x 0.333 + 203 x 0.333 + 209 x 0.333

- Simplification

Average atomic mass = 66.6 + 67.6 + 69.6

Result

Average atomic mass = 203.8 g

3 0

3 years ago