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vladimir2022 [97]
3 years ago
6

What is the smallest part of an element?

Chemistry
2 answers:
GenaCL600 [577]3 years ago
8 0

An atom is the smallest unit of matter that has the properties of an element. It is composed of a dense core called the nucleus and a series of outer shells occupied by orbiting electrons. The nucleus, composed of protons and neutrons, is at the center of an atom.

Explanation:

dangina [55]3 years ago
3 0

Answer:

Explanation:

I am going to guess you mean a atom in which a atom is made of a nucleus and protons neutrons and electrons with electrons being the smallest. But there are even smaller sub atomic particles like leptons and quarks but there are over 200 sub atomic particles and no real way of knowing the smallest.

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Which equation describes the mass of an object in relation to its volume and density? a. m=DV b. m=D×V c. m=D+V d. m=VD
zhenek [66]

Answer:

B

Explanation:

the formula is d=m/v

both sides xV

dv=m

6 0
3 years ago
What will happen to the pH of a solution when the [H+] is increased?
matrenka [14]

Answer:

decreases

Explanation:

the more conc of H ions increases the more it becomes acidic so the pH goes down

8 0
3 years ago
You carry out a titration of a pure weak triprotic acid and only see two major pH jumps. One at 10.0 mL and the second one at 15
mafiozo [28]
23 would be most likely
3 0
3 years ago
A toxicologist studying mustard gas, S(CH2CH2Cl)2, a blistering agent, prepares a mixture of 0.675 M SCl2and 0.973 M C2H4 and al
Musya8 [376]

Answer:

The value of K_p is 0.02495.

Explanation:

Initial concentration of SCL_2 gas = 0.675 M

Initial concentration of C_2H_4 gas = 0.973 M

Equilibrium concentration of mustard gas = 0.35 M

SCl_2 (g) + 2 C_2H_4 (g)\rightleftharpoons S(CH_2CH_2Cl)_2(g)

initially

0.675 M            0.973 M        0

At equilibrium ;

(0.675-0.35) M            (0.973-2 × 0.35) M        0.35 M

The equilibrium constant is given as :

K_c=\frac{[S(CH_2CH_2Cl)_2]}{[SCl_2][C_2H_4]^2}

=\frac{0.35 M}{(0.675-0.35) M\times ((0.973-2 × 0.35) M)^2}

K_c=14.45

The relation between K_p and K_c are :

K_p=K_c\times (RT)^{\Delta n}

where,

K_p = equilibrium constant at constant pressure = ?

K_c = equilibrium concentration constant =14.45

R = gas constant = 0.0821 L⋅atm/(K⋅mol)

T = temperature = 20.0°C =20.0 +273.15 K=293.15 K

\Delta n = change in the number of moles of gas = [(1) - (1 + 2)]=-2

Now put all the given values in the above relation, we get:

K_p=14.45\times (0.0821L.atm/K.mol\times 293.15 K)^{-2}

K_p=6.2\times 10^{4}

K_p=0.02495

The value of K_p is 0.02495.

7 0
3 years ago
What is the conjugate acid in the following equation:
yanalaym [24]

Answer:

HNO₂

Explanation:

An acid is a proton donor; a base is a proton acceptor.

Thus, NO₂⁻ is the base, because it accepts a proton from the water.

H₂O is the acid, because it donates a proton to the nitrite ion.

The conjugate base is what's left after the acid has given up its proton.

The conjugate acid is what's formed when the base has accepted a proton.

NO₂⁻/HNO₂ make one conjugate acid/base pair, and H₂O/OH⁻ are the other conjugate acid/base pair.

NO₂⁻ + H₂O ⇌ HNO₂ + OH⁻

base     acid     conj.      conj.

                        acid       base

5 0
3 years ago
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