An unknown volume of gas has a pressure of 0.50 atm and temperature of 325 K. If the pressure is raised to 1.2 atm and the tempe
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We know the law of conservation of mass
- It states that mass is neither formed nor destroyed in any chemical reaction.
- Mass of reactants=Mass of products.
Here
- Mg and I_2 are reactants
- MgI_2 is product with some yield.
- Mass of reactants=10+60.0=70.0g
- Mass of MgI_2=53.88g
- Mass of yield=Product-MgI_2=70-53.88=16.12g
Lets find the percentage
Answer :
(a) The net ionic equation will be,
The spectator ions are,
(b) The net ionic equation will be,
The spectator ions are,
(c) The net ionic equation will be,
The spectator ions are,
Explanation :
In the net ionic equations, we are not include the spectator ions in the equations.
Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.
(a) The given balanced ionic equation will be,
The ionic equation in separated aqueous solution will be,
In this equation, are the spectator ions.
By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.
The net ionic equation will be,
(b) The given balanced ionic equation will be,
The ionic equation in separated aqueous solution will be,
In this equation, are the spectator ions.
By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.
The net ionic equation will be,
(c) The given balanced ionic equation will be,
The ionic equation in separated aqueous solution will be,
In this equation, are the spectator ions.
By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.
The net ionic equation will be,