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juin [17]
4 years ago
12

What is the ph of a solution that is 0.50 m in propanoic acid and 0.40 m in sodium propanoate. (ka for propanoic acid = 1.3 x 10

-5)?
Chemistry
1 answer:
max2010maxim [7]4 years ago
3 0
<span>The pH is given by the Henderson - Hasselbalch equation:
              pH = pKa + log([A-]/[HA])
              pH = -log(</span><span>1.3 x 10^-5) + log(0.50/0.40)
              pH = 4.98
The answer to this question is 4.98.
</span>
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121.37 moles.

Explanation:

Always one mole of any molecule contains Avogadro number of molecules.

So one mole of methane contains 6.023*10^23 molecules.

Now we need number of moles of methane in 7.31*10^25 molecules.

This is just cross multiplication stuff.

6.023*10^23 molecules —————- 1 mole

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3 years ago
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