What is the ph of a solution that is 0.50 m in propanoic acid and 0.40 m in sodium propanoate. (ka for propanoic acid = 1.3 x 10
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So, according to the above reaction, 1 mole of
So, 0.3 mole will give = 0.3 x 2 = 0.6 moles of
So, Molar concentration =
Note: 1L = 1000mL