First day: 25% × 100 = 25 ( miles)
Second day : the remaining distance is 100 - 25 = 75 ( milesl
Third day: 40% × 75 = 30
25 + 75 + 30 = 130 (miles)
Complete Question
A set of magical wand prices are normally distributed with a mean of 50 dollars and a standard deviation of 4 dollars. A blackthorn wand has a price of 45.20. What proportion of wand prices are lower than the price of the blackthorn wand? You may round your answer to four decimal places
Answer:
0.1151
Step-by-step explanation:
We solve using z score formula
z = (x-μ)/σ, where
x is the raw score = $45.20
μ is the population mean = $50
σ is the population standard deviation = $4
We are solving for x < 45.20
Hence:
z = 45.20 - 50/4
z = -1.2
Probability value from Z-Table:
P(x<45.20) = 0.11507
Approximately to 4 decimal places = 0.1151
Therefore, the proportion of wand prices that are lower than the price of the blackthorn wand is 0.1151
Answer: R=8
Step-by-step explanation: R-7=1, R+7=1+7, R=8.
The probability that the reaction time for this density function is at most 2.5 seconds is equal to 0.9.
<h3>What is a density function?</h3>
A density function can be defined as a type of function which is used to represent the density of a continuous random variable that lies within a specific range.
<h3>How to calculate the probability that reaction time is at most 2.5 seconds?</h3>
P(X ≤ 2.5) = Fx(2.5)
Fx(2.5) = 3/2 - 3/2(2.5)
Fx(2.5) = 3/2 - 3/5
Fx(2.5) = 0.9.
Read more on density function here: brainly.com/question/14448717
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Complete Question:
The reaction time (in seconds) to a certain stimulus is a continuous random variable with pdf:
f(x) = 
What is the probability that reaction time is at most 2.5 seconds?
In an installment loan, a lender loans a borrower a principal amount P, on which the borrower will pay a yearly interest rate of i (as a fraction, e.g. a rate of 6% would correspond to i=0.06) for n years. The borrower pays a fixed amount M to the lender q times per year. At the end of the n years, the last payment by the borrower pays off the loan.
After k payments, the amount A still owed is
<span>A = P(1+[i/q])k - Mq([1+(i/q)]k-1)/i,
= (P-Mq/i)(1+[i/q])k + Mq/i.
</span>The amount of the fixed payment is determined by<span>M = Pi/[q(1-[1+(i/q)]-nq)].
</span>The amount of principal that can be paid off in n years is<span>P = M(1-[1+(i/q)]-nq)q/i.
</span>The number of years needed to pay off the loan isn = -log(1-[Pi/(Mq)])/(q log[1+(i/q)]).
The total amount paid by the borrower is Mnq, and the total amount of interest paid is<span>I = Mnq - P.</span>
