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3 years ago

I will mark brainliest!

1 answer:

3 0

F(x) = a(x - h)2 + k
f(x) = a(x + 2)2 - 7

(0,-3)
-3 = a(0 + 2)2 - 7
4 = a(2)2
4 = 4
1 = a
f(x) = 1(x + 2)2 - 7 = x2 + 4x - 3

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If y varies directly as x and y=4 when x=-2 find y when x=30

katovenus [111]

Answer:

Step-by-step explanation:

y=kx

4=k(-2)

k=-2

y=-2x

when x=30

y=-2*30=-60

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4 years ago

Ben said the graph of the inequality

Ksivusya [100]

Answer:

Ben is incorrect

The solutions are x>-3 and x < 3

Step-by-step explanation:

we have

$-x^{2} +9 > 0$

Multiply by -1 both sides

$x^{2} -9 < 0$

Adds 9 both sides

$x^{2} < 9$

The solutions are

$x < 3$

and

$-x < 3$ -----> Multiply by -1 both sides ----> $x > -3$

therefore

The solution is the interval (-3,3)

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4 years ago

Find the value of X

emmasim [6.3K]

Answer: 20 i think srry if its wrong

Step-by-step explanation:

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3 years ago

Read 2 more answers

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Serjik [45]

$\frac{a}{8} = - 4 \\ = > a \: = - 4 \times 8 \\ = > a \: = - 32 \\$

<h3>Answer is -32.</h3>

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3 years ago

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The population of a town is 6500 and is increasing at a rate of 4% each year. Create a function for this scenario. At this rate,

Stella [2.4K]

Answer:

$P_4 = 7604.08$

Step-by-step explanation:

If the population increases at a rate of 4% per annum, then:

In year 1:

$P_1 = P_0 + 0.04P_0$

Where $P_0$ is the initial population and $P_n$ is the population in year n

In year 2

$P_2 = P_1 + 0.04P_1$

It can also be written as:

$P_2 = P_0 + 0.04P_0 + 0.04 (P_0 + 0.04P_0)$

Taking out common factor $P_0$

$P_2 = (1 + 0.04) (P_0) + 0.04P_0 (1 + 0.04)$

Taking out common factor (1 + 0.04)

$P_2 = (1 + 0.04) (P_0 + 0.04P_0)$

Taking out again common factor $P_0$

$P_2 = (1 + 0.04) (1 + 0.04) P_0$

Simplifying

$P_2 = P_0 (1 + 0.04) ^ 2$

$P_n = P_0 (1 + 0.04) ^ n$

This is the equation that represents the population for year n

Then, in 4 years, the population will be:

$P_4 = P_0 (1 + 0.04) ^ 4\\P_4 = 6500(1 + 0.04) ^ 4\\P_4 = 7604.08$

3 0

4 years ago