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bixtya [17]
3 years ago
14

If an object has more positive charges than negative charges, the object has an overall?

Chemistry
1 answer:
guapka [62]3 years ago
6 0
It will have an overall positive charge.
You might be interested in
How many grams is 5.4x10 to the 23 molecules of al2o3?
8090 [49]

Answer:

91.49 grams

Explanation:

No of molecules = no of moles × Avogadro's number

No of moles = No of molecules / Avogadro's number

Number of moles = 5.4×10^23/6.02×10^23

Number of moles = 0.897 moles of Al2O3

Number of moles = mass in gram / molar mass

Mass in gram = number of moles× molar mass

Mass in gram = 0.897× 102

91.49 grams

5 0
3 years ago
True or false, The universal gas constant, R, is . 0821 when we use mm Hg as our unit for pressure
ludmilkaskok [199]

Answer:

This is true.

Explanation:

R should be 0.0821

Good luck!

5 0
3 years ago
7. Which of the following represents the largest mass?
Tamiku [17]

Answer:

 10kg = 10 x 1000 = 10,000g

Explanation:

To know the quantity with the largest mass, we have to express all the units in grams:

for: 2 x 10mg = 2 x 10 x 10⁻³ = 0.02g

       0.001kg = 0.001 x 1000 = 1g

       1 x 10⁵ng = 1 x 10⁵ x 10⁻⁹ = 0.0001g

       2 x 10²cg = 2 x 10² x 10⁻² = 2g

       10kg = 10 x 1000 = 10,000g

Note:

              10⁻ ¹      deci(d)

              10⁻²       centi(c)

              10⁻³       milli(m)

            10⁻⁹         nano(n)

            10³           kilo(k)

   

5 0
4 years ago
If the number of moles of a gas initially contained in a 2.10 l vessel is doubled, what is the final volume of the gas in liters
Anon25 [30]
Avagadro's law gives the relationship between volume of gas and number of moles of the gas. When the temperature and pressure are constant, volume is directly proportional to number of moles of gas.
\frac{V1}{n1} =  \frac{V2}{n2}
V -volume and n - number of moles of gas.
parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation 
initial number of moles n1 - N
n2 - 2N as the number of moles are doubled 
V1 - initial volume - 2.10 L
V2 - final volume - V
substituting the values in the equation 
\frac{2.10L}{N}  \frac{V}{2N}
V = 4.20 L 
final volume is 4.20 L 
7 0
3 years ago
A student determined that a 50mL sample of an unknown liquid had a density of 1 g/mL. A 100mL sample of the same liquid would ha
Lyrx [107]

Answer: False

Explanation: The density of the liquid will always be the same, no matter how much of the liquid you have.

For example, the density of the water in a pool is the same density as the water in a small cup.

4 0
3 years ago
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