SAMPLE A - <span>pure substance.
</span>SAMPLE B - <span>homogeneous mixture.
</span>SAMPLE C - <span>heterogeneous mixture.
</span>Pure substance - <span>constant composition and properties.</span>
Homogeneous mixture - same uniform appearance and composition.
Heterogeneous mixture - <span>not </span>uniform<span> in composition, two phases (liquid and dust).
</span>
Answer:
The new pressure will be 0.225 kPa.
Explanation:
Applying combined gas law:

where,
are initial pressure and volume at initial temperature
.
are final pressure and volume at initial temperature
.
We are given:



Putting values in above equation, we get:


Hence, the new pressure will be 0.225 kPa.
C6H12O6 +6O2 —> 6CO2 + 6H2O
Answer:
Bacterial cell, cell with a nucleus, multicellular organism
Answer:
Na
Explanation:
sodium has mass number 23 and atomic number 11 so number of protons =number of electrons =atomic number which is 11 and number of neutrons=mass number-number of protons =23-11=12