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2 years ago

Ordinarily, when we talk about green infrastructure, what type of public element are we most likely to be discussing?

1 answer:

6 0

Parks and open spaces
hope that helps if u have any questions let me know and also if u could mark this as brainliest i would really appreciate it!

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How many oxygen molecules are in 22.4 liters of oxygen gas at 273 K and 101.3 kPa?

lora16 [44]

The answer would be 6.023 x 10E23
E= exponent

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3 years ago

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zhenek [66]

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2 years ago

Only valence electrons can be shared stolen or given away<br><br> True <br><br> False

Vesna [10]

Answer:

false

Explanation:

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3 years ago

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Why an offspring and its parent share many common traits?

blondinia [14]

Answer:

Explanation: Traits are characteristics, such as its size or height and that comes from parents or other relatives.

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2 years ago

The normal freezing point of a certain liquid

stepladder [879]

Answer : The molal freezing point depression constant of X is $4.12^oC/m$

Explanation : Given,

Mass of urea (solute) = 5.90 g

Mass of X liquid (solvent) = 450.0 g

Molar mass of urea = 60 g/mole

Formula used :

$\Delta T_f=i\times K_f\times m\\\\T^o-T_s=i\times K_f\times\frac{\text{Mass of urea}\times 1000}{\text{Molar mass of urea}\times \text{Mass of X liquid}}$

where,

$\Delta T_f$ = change in freezing point

$\Delta T_s$ = freezing point of solution = $-0.5^oC$

$\Delta T^o$ = freezing point of liquid X= $0.4^oC$

i = Van't Hoff factor = 1 (for non-electrolyte)

$K_f$ = molal freezing point depression constant of X = ?

m = molality

Now put all the given values in this formula, we get

$[0.4-(-0.5)]^oC=1\times k_f\times \frac{5.90g\times 1000}{60g/mol\times 450.0g}$

$k_f=4.12^oC/m$

Therefore, the molal freezing point depression constant of X is $4.12^oC/m$

4 0

3 years ago