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musickatia [10]
2 years ago
13

Truse or false

Mathematics
2 answers:
LUCKY_DIMON [66]2 years ago
8 0

Answer:true

i hope it help you :) <3

Step-by-step explanation:

svetlana [45]2 years ago
5 0

Answer:

True

Step-by-step explanation:

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What is the simplified form of the equation fraction 4 over 5 n minus fraction 1 over 5 equals fraction 2 over 5 n
liubo4ka [24]
4/5n – 1/5 = 2/5n
Add 1/5 to both sides
4/5n = 2/5n + 1/5
Subtract 2/5n from both sides
2/5n = 1/5
Divide both sides by 2/5

n = 1/2
8 0
3 years ago
Which of the binomials below is a factor of this trinomial?<br> x^2- 14x+ 24
Ray Of Light [21]

Answer:

(x-2)(x-12)

Step-by-step explanation:

x^2-14x+24=(x-2)(x-12)

5 0
3 years ago
What should n be if f (x) = x^n defines a polynomial function?
Aleks04 [339]

9514 1404 393

Answer:

  a non-negative integer

Step-by-step explanation:

Powers of variables in a polynomial are whole numbers, that is, non-negative integers.

For f(x) to be a polynomial function, the value of n must be a whole number.

3 0
2 years ago
3 ½ times as many guests arrived as were expected. If 105 guests were unexpected, how many guests were expected ?
lara [203]
Let x be the expected number Number arriving = 3•5 x Unexpected number 2•5 x 2•5 x = 105 10x = 420 x = 42______Option D
8 0
3 years ago
Suppose a consumer product researcher wanted to find out whether a highlighter lasted less than the manufacturer's claim that th
11111nata11111 [884]

Answer:

The null hypothesis is H_0: \mu = 14

The alternate hypothesis is H_a: \mu < 14

The test statistic is t = -1.95.

The p-value is of 0.0292. This means that for a level of significance of 0.0292 and higher, there is sufficient evidence to conclude that the  highlighters wrote for less than 14 continuous hours.

Step-by-step explanation:

Suppose a consumer product researcher wanted to find out whether a highlighter lasted less than the manufacturer's claim that their highlighters could write continuously for 14 hours.

At the null hypothesis, we test if the mean is 14 hours, that is:

H_0: \mu = 14

At the alternate hypothesis, we test if the mean is less than 14 hours, that is:

H_a: \mu < 14

The test statistic is:

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, s is the standard deviation of the sample and n is the size of the sample.

14 is tested at the null hypothesis:

This means that \mu = 14

X = 13.6 hours, s = 1.3 hours. Sample of 40:

In addition to the values of X and s given, we have that n = 40

Test statistic:

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{13.6 - 14}{\frac{1.3}{\sqrt{40}}}

t = -1.95

The test statistic is t = -1.95.

P-value:

The p-value of the test is the probability of finding a sample mean lower than 13.6, which is a left tailed test, with t = -1.95 and 40 - 1 = 39 degrees of freedom.

Using a calculator, the p-value is of 0.0292. This means that for a level of significance of 0.0292 and higher, there is sufficient evidence to conclude that the  highlighters wrote for less than 14 continuous hours.

5 0
2 years ago
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