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dlinn [17]
3 years ago
7

What is the degree of the monomial -9x^4?

Mathematics
1 answer:
devlian [24]3 years ago
3 0

Answer:

4 because 4 is the exponent

Step-by-step explanation:

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Calculate:
Nadya [2.5K]

Answer:

13.64 litres

Explanation

Since 1 gallon = 4.546 litres

Therefore...3 gal

; 3 × 4.546 = 13.64 litres

8 0
3 years ago
The number of chocolate chips in a bag of chocolate chip cookies is approximately normally distributed with mean of 1262 and a s
Andrew [12]

Answer:

a) 1186

b) Between 1031 and 1493.

c) 160

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Normally distributed with mean of 1262 and a standard deviation of 118.

This means that \mu = 1262, \sigma = 118

a) Determine the 26th percentile for the number of chocolate chips in a bag. ​

This is X when Z has a p-value of 0.26, so X when Z = -0.643.

Z = \frac{X - \mu}{\sigma}

-0.643 = \frac{X - 1262}{118}

X - 1262 = -0.643*118

X = 1186

(b) Determine the number of chocolate chips in a bag that make up the middle 95% of bags.

Between the 50 - (95/2) = 2.5th percentile and the 50 + (95/2) = 97.5th percentile.

2.5th percentile:

X when Z has a p-value of 0.025, so X when Z = -1.96.

Z = \frac{X - \mu}{\sigma}

-1.96 = \frac{X - 1262}{118}

X - 1262 = -1.96*118

X = 1031

97.5th percentile:

X when Z has a p-value of 0.975, so X when Z = 1.96.

Z = \frac{X - \mu}{\sigma}

1.96 = \frac{X - 1262}{118}

X - 1262 = 1.96*118

X = 1493

Between 1031 and 1493.

​(c) What is the interquartile range of the number of chocolate chips in a bag of chocolate chip​ cookies?

Difference between the 75th percentile and the 25th percentile.

25th percentile:

X when Z has a p-value of 0.25, so X when Z = -0.675.

Z = \frac{X - \mu}{\sigma}

-0.675 = \frac{X - 1262}{118}

X - 1262 = -0.675*118

X = 1182

75th percentile:

X when Z has a p-value of 0.75, so X when Z = 0.675.

Z = \frac{X - \mu}{\sigma}

0.675 = \frac{X - 1262}{118}

X - 1262 = 0.675*118

X = 1342

IQR:

1342 - 1182 = 160

7 0
3 years ago
When Carson runs the 400 meter dash, his finishing times are normally distributed with a mean of 65 seconds and a standard devia
just olya [345]

Given Information:  

Mean time to finish 400 meter dash  = μ = 65 seconds

Standard deviation to finish 400 meter dash = σ = 2.5 seconds  

Confidence level = 95%

Required Information:  

95% confidence interval = ?

Answer:  

 CI = 60 \: to \: 70 \: seconds

Step-by-step explanation:  

In the normal distribution, the empirical rule states approximately 68% of all the data lie within 1 standard deviation from the mean, approximately 95% of all the data lie within 2 standard deviations from the mean and approximately 99.7% of all the data lie within 3 standard deviations from the mean.

The confidence interval for 95% confidence limit is given by

 CI = \mu \pm 2\sigma

Since approximately 95% of all the data lie within 2 standard deviations from the mean. μ is the mean time Carson takes to finish 400 meter dash and σ is the standard deviation.

 CI = 65 \pm 2(2.5)

 CI = 65 \pm 5

 CI = 65 - 5 \: to \: 65 + 5

CI = 60 \: to \: 70 \: seconds

Therefore, the 95% confidence interval is between 60 to 70 seconds

What does it mean?  

It means that we are 95% confident that the Carson's mean to finish 400 meter dash is within the interval of (60, 70).

4 0
3 years ago
What is the formula for finding the volume of a cube?<br><br> 2x*x<br><br> E^3<br><br> 2*x=3x(3+4)
ludmilkaskok [199]
To find the volume for a cube you need to do length x width x height. make sure you put it as cm3 because it’s volume. hope it helps?
3 0
2 years ago
Read 2 more answers
The graph compares the weights in pounds of 100 dogs and cats that are brought in to a veterinarian's office.
GenaCL600 [577]
In case of dogs the value 10 is the minimum value. So all the values lie above 10. In total there were 100 dogs.
So for dogs, we can say number of dogs above the value of 10 pound are 100.

In case of Cats, 10 lies at the position of median. Median is the central value and 50% values lie above the median value. So number of cats with weight above 10 pound is 50.

Thus, we can conclude that there were 50 more dogs than the cats with weight over 10 pounds. So option C gives the correct answer.
8 0
3 years ago
Read 2 more answers
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