Answer:
step 1
Find the average growth per year of the populations of rabbits farm A
Over the first 2 years
for t=0
numbers of rabbits=5 (is not exact)
for t=2
numbers of rabbits=40
average=[40-5]/2---------> 17.5
step 2
Find the average growth per year of the populations of rabbits farm B
Over the first 2 years
for t=0
numbers of rabbits=5 (is not exact)
for t=2
numbers of rabbits=30
average=[30-5]/2---------> 12.5
step 3
Compare the average growth per year of the populations of rabbits on both farms
farm A=17.5
farm B=12.5
the average rate of population growth of rabbits in farm A is greater than average rate of population growth of rabbits in farm B by about 5 rabbits per year.
therefore
the answer is the option C)
the average rate of population growth of rabbits in farm A is greater than average rate of population growth of rabbits in farm B by about 6 rabbits per year.
Step-by-step explanation:
I'm not quite sure what you asking here but if your asking how to answer it in "math terms" than I'll be happy to explain :)
So "times" means multiply and "increase" means add so righting this in math terms would be
6x + 5
because it's six times "a number" which you can replace with x!
Let me know if you have any questions :3
Answer:
$20
Step-by-step explanation:
7 x __=70
2 x ____=___
7 x 10 = 70
2 x 10
=20
Answer:
a
Step-by-step explanation:
