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n200080 [17]
3 years ago
11

Evaluate 3xy- y + 6z when x = 1, y = - 2 and z = 3

Mathematics
2 answers:
Elanso [62]3 years ago
5 0

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{14}}}}}

Step-by-step explanation:

Given, x = 1 , y = -2 , z = 3

\sf{3xy - y + 6z}

Plug the value of x , y and z

⇒\sf{3 \times 1 \times  ( - 2) - ( - 2) + 6 \times 3}

Multiply the numbers

⇒\sf{ - 6 - ( - 2) + 6 \times 3}

We know that , \sf{( - ) \times ( - ) = ( + )}

⇒\sf{ - 6 + 2 + 6 \times 3}

Multiply the numbers : 6 and 3

⇒\sf{ - 6 + 2 + 18}

Add the numbers : 2 and 18

⇒\sf{ - 6 + 20}

Calculate the difference

⇒\sf{14}

Hope I helped !

Best regards!!

Marat540 [252]3 years ago
4 0

Answer:

<h2>14</h2>

Step-by-step explanation:

3xy- y + 6z \\\\x = 1\\ y = - 2 \\ z = 3\\\\3(1)(-2) - (-2) +6(3)\\-6 + 2 +18\\=14

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