Question

Evaluate 3xy- y + 6z when x = 1, y = - 2 and z = 3

Answer 1

Answer:

$\boxed{ \bold{ \huge{ \boxed{ \sf{14}}}}}$

Step-by-step explanation:

Given, x = 1 , y = -2 , z = 3

$\sf{3xy - y + 6z}$

Plug the value of x , y and z

⇒$\sf{3 \times 1 \times ( - 2) - ( - 2) + 6 \times 3}$

Multiply the numbers

⇒$\sf{ - 6 - ( - 2) + 6 \times 3}$

We know that , $\sf{( - ) \times ( - ) = ( + )}$

⇒$\sf{ - 6 + 2 + 6 \times 3}$

Multiply the numbers : 6 and 3

⇒$\sf{ - 6 + 2 + 18}$

Add the numbers : 2 and 18

⇒$\sf{ - 6 + 20}$

Calculate the difference

⇒$\sf{14}$

Hope I helped !

Best regards!!

Answer 2

Answer:

14

Step-by-step explanation:

$3xy- y + 6z \\\\x = 1\\ y = - 2 \\ z = 3\\\\3(1)(-2) - (-2) +6(3)\\-6 + 2 +18\\=14$