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Law Incorporation [45]
3 years ago
14

Solve for h. A=7h ... X Х 5

Mathematics
1 answer:
BaLLatris [955]3 years ago
3 0
A=h7
divide both sides by h
A\7=h
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How many terms are in the following expression?<br> 3x + 7 - (-4b) + 2x + (-b) + 5
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Answer:

-5b+5x+12

Step-by-step explanation:

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What number must be added to both sides of the equation to complete the square ?
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First consider (x+c)^2 where c is just a random constant. if we expand this by foil (which is distributive property twice), we get x^2 + 2cx+ c^2. we want to find c^2 and to do that, we can first find c. we can find c by looking at the 2cx term. this term should match with 12x, so therefore 2c = 12 so c = 6. this also implies that c^2 = 36.
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3 years ago
X^2+4x+20=12x-5<br><br> Solve this equation
Scrat [10]

Answer:

4 + (or -) 3i

Step-by-step explanation:

Hi!

Alright, so we're going to move all of the variables and constants to one side. Then, using the quadratic formula, we'll find the answer.

1. Move 12x-5 to the left side of the equation by

  a. Subtracting 12x from both sides

  b. adding 5 to both sides.

1: x^2+4x+20-12x+5

2. Group the common terms

  x^2+4x-12x+20+5 --> x^2-8x+25

3. Look at the problem. We can't factor this.

Explanation for why this isn't factorable (you can skip this)

(1) 25 is positive, so its two factors will both be either positive or negative. We're looking for a negative 8, so let's go with negative.

(2) Factors of 25: 1 & 25, 5 &5

Seeing the problem? Ya, none of the factors of 25 sum to eight. So, instead, we're going to use the quadratic formula.

4.  So, the quadratic formula: \frac{-b+-\sqrt{b^2-4ac} }{2a}

Our equation is x^2-8x+25=0

a is the constant in front of the x^2

b is the constant in front of the x

c is the term without any x values

so, a=1, b=-8, and c= 25

Into equation:

\frac{8+-\sqrt{64-4(1)(25)} }{2a}=\frac{8+-\sqrt{64-100} }{2}=\frac{8+-\sqrt{-36} }{2}

8/2 = 4

sqrt(-36) = 6i

6i/2 = 3i (remember, we still have the two in the denominator)

4 + (or -) 3i

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