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3 years ago

What is the median of these numbers 10, 12, 8, 11, 10, 15, 7

Mathematics

2 answers:

olga2289 [7]3 years ago

6 0

Answer:

Step-by-step explanation:

AMOGUS (again)

prohojiy [21]3 years ago

3 0

Answer:

answer is 11.

Step-by-step explanation:

the median is always the middle

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Let f (x) = 1/x<br> and g(x) = x² – 3x. What<br> two numbers are not in the domain of fºg?

iren [92.7K]

For this case we have the following equations:

$f (x) = \frac {1} {x}\\g (x) = x ^ 2-3x$

We must find $(f_ {o} g) (x):$

By definition of composition of functions we have to:

$(f_ {o} g) (x) = f (g (x))$

So:

$(f_ {o} g) (x) = \frac {1} {x ^ 2-3x}$

We must find the domain of f (g (x)). The domain will be given by the values for which the function is defined, that is, when the denominator is nonzero.

$x ^ 2-3x = 0\\x (x-3) = 0$

So, the roots are:

$x_ {1} = 0\\x_ {2} = 3$

The domain is given by all real numbers except 0 and 3.

Answer:

x other than 0 and 3

8 0

3 years ago

Read 2 more answers

This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive an

sleet_krkn [62]

Answer:

-6re−r [sin(6θ) - cos(6θ)]

Step-by-step explanation:

the Jacobian is ∂(x, y) /∂(r, θ) = δx/δθ × δy/δr - δx/δr × δy/δθ

x = e−r sin(6θ), y = er cos(6θ)

δx/δθ = -6rcos(6θ)e−r sin(6θ), δx/δr = -sin(6θ)e−r sin(6θ)

δy/δθ = -6rsin(6θ)er cos(6θ), δy/δr = cos(6θ)er cos(6θ)

∂(x, y) /∂(r, θ) = δx/δθ × δy/δr - δx/δr × δy/δθ

= -6rcos(6θ)e−r sin(6θ) × cos(6θ)er cos(6θ) - [-sin(6θ)e−r sin(6θ) × -6rsin(6θ)er cos(6θ)]

= -6rcos²(6θ)e−r (sin(6θ) - cos(6θ)) - 6rsin²(6θ)e−r (sin(6θ) - cos(6θ))

= -6re−r (sin(6θ) - cos(6θ)) [cos²(6θ) + sin²(6θ)]

= -6re−r [sin(6θ) - cos(6θ)] since [cos²(6θ) + sin²(6θ)] = 1

6 0

3 years ago

Find the length of an arc formed by a 90 degree angle on a circle with a radius of 6 the hcc

zvonat [6]

The length of that arc is (90/360)·2·π·6 = (1/4)·12·π = 3·π ≈ 9.42 units;

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3 years ago

When calculating the successive discounts of 15% and 10% on a $100 item, _____. a. take 10% of $85 b. take 10% of $90 c. take 15

LekaFEV [45]

10% of 100$ is the answer

7 0

2 years ago

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10x3−8x2−12x2x simplify

atroni [7]

10x^3-8x^2-12x^2(x)
10x^3-8x^2-12x^3
-2x^3-8x^2
=-2x^2(x+4)

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2 years ago