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const2013 [10]
3 years ago
12

DRIVERS ED(TRUE OR FALSE) When passing another vehicle you must be able to complete the pass by returning to the right side befo

re coming within a distance of at least 100 feet of any oncoming vehicles.
True
False
Mathematics
2 answers:
Natasha2012 [34]3 years ago
5 0

Answer:

IT IS TRUE

Step-by-step explanation:

PLS MARK ME AS BRAINLIEST PLS PLS

Evgesh-ka [11]3 years ago
3 0

Answer:

It

Step-by-step explanation:

Is true because if you didn’t, who know what would happen

You might be interested in
Solve the equation. Round your answer to the nearest hundredth.<br> 47 +3.81k = -41
Harman [31]

Answer:

i have no idea but if i had to guess it would be around   -3.00k or -4.00k

Step-by-step explanation:

4 0
3 years ago
A survey was conducted two years ago asking college students their top motivations for using a credit card. To determine whether
salantis [7]

Answer:

See explanation

Step-by-step explanation:

Solution:-

- A survey was conducted among the College students for their motivations of using credit cards two years ago. A randomly selected group of sample size n = 425 college students were selected.

- The results of the survey test taken 2 years ago and recent study are as follows:

                                           

                                           Old Survey ( % )            New survey ( Frequency )

                  Reward                 27                                              112

                  Low rate               23                                              96

                  Cash back           21                                              109

                  Discount              9                                               48

                  Others                  20                                             60

- We are to test the claim for any changes in the expected distribution.

We will state the hypothesis accordingly:

Null hypothesis: The expected distribution obtained 2 years ago for the motivation behind the use of credit cards are as follows: Rewards = 27% , Low rate = 23%, Cash back = 21%, Discount = 9%, Others = 20%

Alternate Hypothesis: Any changes observed in the expected distribution of proportion of reasons for the use of credit cards by college students.

( We are to test this claim - Ha )

We apply the chi-square test for independence.

- A chi-square test for independence compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each other.

- We will compute the chi-square test statistics ( X^2 ) according to the following formula:

 

                                X^2 = Sum [ \frac{(O_i - E_i)^2}{Ei} ]

Where,

 O_i : The observed value for ith data point

 E_i : The expected value for ith data point.

- We have 5 data points.

So, Oi :Rewards = 27% , Low rate = 23%, Cash back = 21%, Discount = 9%, Others = 20% from a group of n = 425.

     Ei : Rewards = 112 , Low rate = 96, Cash back = 109, Discount = 48, Others = 60.

Therefore,

                               

                     X^2 = [ \frac{(112 - 425*0.27)^2}{425*0.27} +  \frac{(96 - 425*0.23)^2}{425*0.23} +  \frac{(109 - 425*0.21)^2}{425*0.21} +  \frac{(48 - 425*0.09)^2}{425*0.09} +  \frac{(60 - 425*0.20)^2}{425*0.20}]\\\\X^2 = [ 0.06590 + 0.03132 + 4.37044 +  2.48529 +  7.35294]\\\\X^2 = 14.30589

- Then we determine the chi-square critical value ( X^2- critical ). The two parameters for evaluating the X^2- critical are:

                     Significance Level ( α ) = 0.10

                     Degree of freedom ( v ) = Data points - 1 = 5 - 1 = 4  

Therefore,

                     X^2-critical = X^2_α,v = X^2_0.1,4

                    X^2-critical = 7.779

- We see that X^2 test value = 14.30589 is greater than the X^2-critical value = 7.779. The test statistics value lies in the rejection region. Hence, the Null hypothesis is rejected.

Conclusion:-

This provides us enough evidence to conclude that there as been a change in the claimed/expected distribution of the motivations of college students to use credit cards.

6 0
4 years ago
Let f(x) = x + 8 and g(x) = x2 − 6x − 7. Find f(g(2)). (1 point)
pantera1 [17]
Hello,

f(x)=x+8
g(x)=x²-6x-7
f(g(x))=f(x²-6x-7)=x²-6x-7+8=x²-6x+1

f(g(2))=2²-6*2+1=4-12+1=-8+1=-7

Answer A
4 0
3 years ago
Log5 (x squared - 9) = 0
andreev551 [17]

Answer:

x=3,\:x=-3

Step-by-step explanation:

Given the equation

\log _{10}\left(5\right)\left(x^2-9\right)=0

Divide both sides by \log _{10}\left(5\right)

\frac{\log _{10}\left(5\right)\left(x^2-9\right)}{\log _{10}\left(5\right)}=\frac{0}{\log _{10}\left(5\right)}

Simplify

x^2-9=0

Add 9 to both sides

x^2-9+9=0+9

Simplifying

x^2=9

\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}

x=\sqrt{9},\:x=-\sqrt{9}

as

\sqrt{9}\:=3

-\sqrt{9}=-3

Therefore,

x=3,\:x=-3

3 0
3 years ago
DO NOT TRY TO ANSWER IF YOU DO NOT KNOW THE ANSWER
Fantom [35]

Answer:

C) 120

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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