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hichkok12 [17]
3 years ago
12

Help!!

Chemistry
2 answers:
castortr0y [4]3 years ago
7 0

Answer:

Lithosphere, Hydrosphere, atmosphere

AysviL [449]3 years ago
3 0

Answer:

Lithosphere, hydrosphere, atmosphere

Explanation:

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What temperature kelvin would .97mol of gas be to occupy 26L at 751.2mmHg?
crimeas [40]

Answer: 322.56 Kelvin

Explanation:

Use the Ideal Gas Law

PV=nRT

R is the gas constant

T is the temperature in Kelvins

P is the pressure in atmospheres

V is the volume in liters

n is the number of moles of gas

First, the mm of mercury need to be converted to atmospheres using the conversion factor 1atm = 760 torr.

751.2mmHg (torr) =0.988atm

Now plug everything in

(0.988)(26)=(0.97)(0.0821)T\\T=322.56K

5 0
3 years ago
Write the mole ratios of (2ca+o2➡2cao)
tresset_1 [31]
N(Ca)/2 = n(O)/1 = n(CaO)/2

The calcium and the Calcium Oxide are divided by 2 because of their coefficients
there is no number in front of the oxygen so it is over one.
Hope this helped!!
6 0
3 years ago
Read 2 more answers
Geologists obtain indirect evidence about Earth’s interior by a. measuring pressure differences at Earth’s surface. b. estimatin
Aleksandr [31]
The appropriate answer is d. recording and studying seismic waves. Seismic waves behave differently as the enter the different layers of the Earth. Scientists used seismic or earthquake waves to determine the different layers of the Earth. The behaviour of the waves as they move through the layers helped scientists identify the boundaries and the state of each layer; solid or liquid.
8 0
3 years ago
Read 2 more answers
HSiCl3+H2O=H10Si10O15+HCl
tiny-mole [99]

10 HSiCl3+ 15 H2O→H10Si10O15+ 30 HCl

Explanation:

Step 1: To make Si equal on both sides. put 10 in front of HSiCl3

10 HSiCl3+ H2O →H10Si10O15+ HCl

Step 2: By putting 30 in front of HCl, Cl can be balanced

10 HSiCl3+ H2O →H10Si10O15+ 30 HCl

Step 3: Now, balance O by putting 15 in front of H2O

10 HSiCl3+ 15 H2O→H10Si10O15+ 30 HCl

Hence the balanced equation is:

10 HSiCl3+ 15 H2O→H10Si10O15+ 30 HCl

5 0
4 years ago
What is the new freezing point for a 0.811m solution of Li2O in water?
rewona [7]

Answer:

Freezing T° of solution = - 4.52°C

Explanation:

ΔT = Kf . m . i

That's the formula for colligative property about freezing point depression.

Li₂O is an oxide that can not be dissociated but, if we see it's a ionic compound.

Li₂O →  2Li⁺  +  O⁻²

3 moles of ions have been formed. Ions dissolved in solution are i, what we call Van't Hoff factor.

m is molality → 0.811 m, this is data

Kf →Cryoscopic constant, for water is 1.86 °C/m

and ΔT = Freezing T° of pure solvent - Freezing T° of solution

We replace: 0°C - Freezing T° of solution = 1.86°C/m . 0.811 m . 3

Freezing T° of solution = - 4.52°C

3 0
3 years ago
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