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liubo4ka [24]
3 years ago
8

How much energy is required to heat 40g of water from -7 degrees Celsius to 108 degrees Celsius (Lf= 335,000J/Kg for ice)

Chemistry
1 answer:
solniwko [45]3 years ago
6 0
The   energy  required  to heat  40g  of water  from -7 c  to 108 c is
1541000  joules

     calculation

Q(heat)=  M( mass)  x c(specific heat capacity) xdelta t( change in temperature)

M=  40g=  40/1000= 0.04 Kg
C=  335,000 j/kg/c
delta T   (    108 --7= 115  c)

Q  is therefore   =  0.04 g x  335000 j/kg/c  x 115 c  = 1541,000  joules


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The cell potential of a redox reaction occurring in an electrochemical cell under any set of temperature and concentration condi
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Answer : The actual cell potential of the cell is 0.47 V

Explanation:

Reaction quotient (Q) : It is defined as the measurement of the relative amounts of products and reactants present during a reaction at a particular time.

The given redox reaction is :

Ni^{2+}(aq)+Zn(s)\rightarrow Ni(s)+Zn^{2+}(aq)

The balanced two-half reactions will be,

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Reduction half reaction : Ni^{2+}+2e^-\rightarrow Ni

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In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.

Now put all the given values in this expression, we get

Q=\frac{(0.0141)}{(0.00104)}=13.6

The value of the reaction quotient, Q, for the cell is, 13.6

Now we have to calculate the actual cell potential of the cell.

Using Nernst equation :

E_{cell}=E^o_{cell}-\frac{RT}{nF}\ln Q

where,

F = Faraday constant = 96500 C

R = gas constant = 8.314 J/mol.K

T = room temperature = 316 K

n = number of electrons in oxidation-reduction reaction = 2 mole

E^o_{cell} = standard electrode potential of the cell = 0.51 V

E_{cell} = actual cell potential of the cell = ?

Q = reaction quotient = 13.6

Now put all the given values in the above equation, we get:

E_{cell}=0.51-\frac{(8.314)\times (316)}{2\times 96500}\ln (13.6)

E_{cell}=0.47V

Therefore, the actual cell potential of the cell is 0.47 V

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