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MrRissso [65]
3 years ago
6

Briefly explain the observed effect of the acetylcholine concentration on the rate of the enzyme-catalyzed reaction

Chemistry
1 answer:
Goryan [66]3 years ago
4 0
<h2>Increase of reaction rate</h2>

Explanation:

  • It is observed that when the concentration of acetylcholine remains constant in the reaction of an aqueous solution, the speed of the enzyme-catalyzed reaction or the formation of the product increases with increasing concentrations of substrate.
  • The reaction rate is directly proportional to the concentration of acetylcholine.  
  • At very low concentrations of acetylcholine, there is a small increase in the concentration of the substrate which results in a large increase of the rate in reaction.
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Write a balanced chemical equation for the standard formation reaction of gaseous formaldehyde CH2O
Free_Kalibri [48]
From the combustion of octane, the formaldehyde will be formed as this equation:

C8H18 +  O2 → CH2O + H2O   this is the original equation but it is not a balanced equation, so let's start to balance it: 

the equation to be balanced so the number of atoms on the right side of the equation sholud be equal with the number of atoms on the lef side.

-we have 8 C atoms on left side and 1 atom on the right side so we will try putting 8 CH2O on the right side instead of CH2O

C8H18 + O2 → 8 CH2O + H2O 

we have 2 O atoms on the left side and  9 atoms on the right side so we will try first to put 9 O2 instead of O2 on the left side and put 2H2O on the right side and put  16 CH2O instead of 8 CH2O to make the atoms of O are equal on both sides = 18 atoms

C8H18 + 9 O2 →  16 CH2O + 2H2O 

put now we have 8 atom C on the left side and 16 atom on the right side so, we will put 2 C8H18 instead of C8H18 now we get this equation:

2C8H18 + 9O2 →16 CH2O + 2H2O

-now we have 36 of H atoms on both sides.

- and 16 of C atoms on both sides.

- and 18 of O atoms on both sides.

now all the number of atoms of O & C & H are equal on both sides

∴ 2C8H18 + 9O2 → 16 CH2O + 2 H2O 

is the final balanced equation for the formation of formaldehayde
5 0
3 years ago
I WILL GIVE U BRAINLY !!!!The diagram shown is an example of the element
motikmotik
Your answer is a, boron. Boron has 5 protons, 6 neutrons, and 5 electrons. Hope this helps!
3 0
3 years ago
Read 2 more answers
Which member of the following pairs has the larger London dispersion forces?
Virty [35]

Answer:

H₂S; CO₂; SiH₄

Explanation:

London dispersion forces are larger in molecules that are large and have more atoms or electrons.

A. H₂O or H₂S

H₂S. S is below O in the Periodic Table, so it is the larger atom. Its electrons are more polarizable.

B. CO₂ or CO

CO₂. CO₂ has more atoms. It is also linear, so the molecules can get close to each other and maximize the attractive forces.

C. CH₄ or SiH₄

CH₄. Si is below C in the Periodic Table, so it is the larger atom. Its electrons are more polarizable.

4 0
3 years ago
I really need the answers please!
krek1111 [17]

1) D = 13.6 g / mL

2)ethyl alcohol weighs 158g

3)ρ _copper = 8.9 g cm^{3}

Explanation:

1)

D = m / V

=306.0 g / 22.5 mL

D= 13.6 g / mL

2)

density = mass / volume

mass = density × volume  

=0.789g /ml × 200.0 ml

M=158g

Ethyl alcohol weighs 158g

3)

ρ  (density) = Mass  / Volume

ρ _copper = 1896 g / 8.4cm × 5.5cm × 4.6cm

= 1896g / 212.5 cm^{3}

ρ _copper=8.9 g cm^{3}

4 0
3 years ago
The process of fermentation involves chemical reactions that convert solid glucose (C6H12O6) into aqueous ethanol and carbon dio
e-lub [12.9K]

Answer:

C6H12O6 —> 2C2H5OH + 2CO2

Explanation:

The equation for the reaction is given below:

C6H12O6 —> C2H5OH + CO2

We can balance the equation above as follow:

There are 12 atoms of H on the left side and 6 atoms of the right side. It can be balance by putting 2 in front of C2H5OH as shown below:

C6H12O6 —> 2C2H5OH + CO2

There are 6 atoms of C on the left side and 5 atoms on the right side. It can be balance by putting 2 in front of CO2 as shown below:

C6H12O6 —> 2C2H5OH + 2CO2

Now the equation is balanced.

4 0
3 years ago
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