You need to use q = mc(delta t)
<span>Solve for c: </span>
<span>c = q / m(delta t) </span>
<span>q = 55.o J </span>
<span>m = 11.0 g </span>
<span>delta t = 24.5 - 13.0 = 11.5 deg C </span>
<span>c = 55 J / 11.0 g)(11.5 C) </span>
<span>c = 0.435 J/ g C</span>
<span>Gamma radiation has a shorter wavelength, a higher frequency and higher energy than radio radiation.
Wavelength is inverse to frequency and energy (i.e. higher wavelength means lower frequency and lower energy, and vice versa).</span>
Radioisotopes are used to study chemical reactions because of the fact that they attach radioactive isotopes to certain atoms.<span> Tracer radioisotopes used to study chemical reactions in molecular structures by adding radioistopes to reactants and using the uptake compared to the original isotope. </span>
Group 2 contains soft, silver metals that are less metallic in character than group 1 elements. There is a fairly strong conductivity trend within each row, left to right, and a weaker trend top to bottom. The elements in group 2 are moderately good conductors, while the elements on the right are very poor conductors. <span>As you move vertically between rows, conductivity decreases overall, but slowly.
Group 2 have a generally low electronegativity. Electronegativity decreases moving left and down across the table.</span>
Answer:
2Fe(s) + 3Cl2(g) → 2FeCl3(s)
Explanation:
Step 1: Data given
iron = Fe = solid = Fe(s)
chlorine = Cl2 = gas = Cl2(g)
iron(III) chloride = FeCl3 = solid = FeCl3(s)
Step 2: The unbalanced equation
Fe(s) + Cl2(g) → FeCl3(s)
Step 3: Balancing the equation
Fe(s) + Cl2(g) → FeCl3(s)
On the left we have 2x Cl (in Cl2) and on the right side we have 3x Cl (in FeCl3). To balance the amount of Cl we have to multiply Cl2 (on the left) by 3 and FeCl3 by 2.
Fe(s) + 3Cl2(g) → 2FeCl3(s)
On the left side we have 1x Fe and on the right side we have 2x Fe (in 2FeCl3). To balance the amount of Fe, we have to multiply Fe on the left side by 2. Now the equation is balanced.
2Fe(s) + 3Cl2(g) → 2FeCl3(s)
