Answer is: the mass of the neon gas is closest to
7.8 grams.<span>
</span>
<span>V(neon) = 3.2 L;
volume.
T = 330 K; temperature of gas.
p = 3.3 atm; pressure of gas.
R = 0.08206 L·atm/mol·K; gas constant.
Ideal gas law: p·V = n·R·T.
n = p·V / R·T.
n(neon) = 3.3 atm · 3.2 L / 0.08206
L·atm/mol·K · 330 K.
n(Ne) = 0.389 mol; amount of substance.</span>
m(Ne) = n(Ne) · M(Ne).
m(Ne) = 0.389 mol · 20.2 g/mol.
m(Ne) = 7.878 g; mass of neon.
For the answer to the question above, <span>17.9 x 1.74 gram Mg = 31.15 gram Mg = (31.15/24.31) = 1.28 mole Mg </span>
<span>2 Mg + O2 ---> 2MgO </span>
<span>so 1.28 mole Mg reacts with 0.641 mole O2
I hope my answer helped you. Feel free to ask more questions. Have a nice day!</span>
Because there are a lot of transition metals.
Answer:
Energy released = 
Explanation:
Amount of fissionable material = 2.5 kg
Mass defect = 0.10 % of fissionable material
Mass defect 
Where,
m = Mass defect in Kg
C = Speed of light m/s2
Now substitute the values in the above equation
