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3 years ago

A train travels at 20m/s for 30 seconds.How far has it moved?

Physics

1 answer:

Colt1911 [192]3 years ago

5 0

Answer:

600m

Explanation:

We can use the equation speed = distance / time.

We are trying to find the distance, so rearrange to get distance = speed x time.

Substituting in our values, 20m/s x 30s = 600m

Hope this helps, let me know if you have any questions!

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When cattle are processed, what is the most likely use for the animals' skin?

galben [10]

When cattle are processed, the most likely use for the animals' skin is in

the production of Leather.

<h3 /><h3>Animals used for Leather production</h3>

Cattle

Goat

Crocodile etc.

The commonly used animals in leather production is however cattle and

they amount for a large percentage of leather present today. They also

involve various techniques such as tanning and crusting to ensure

conversion to leather.

Read more about Leather here brainly.com/question/2494725

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3 years ago

What is the state of an object accelerating due to the force of gravity alone?

Marysya12 [62]

Answer:

Its state is in uniformly accelerated motion

Explanation:

When an object is acted upon the force of gravity only, we said that the object is in free fall.

According to Newton's second law of motion:

$F=ma$

where F is the net force on an object, m is its mass, a its acceleration, when the net force on an object (F) is non-zero, than the object accelerates (because a is non-zero), so the object is in accelerated motion.

In case of free fall, the rate of acceleration of the object is equal to $g=9.8 m/s^2$ , the acceleration due to gravity, and it is constant. So, the object is moving by uniformly accelerated motion.

5 0

4 years ago

A railroad car moving at a speed of 3.46 m/s overtakes, collides and couples with two coupled railroad cars moving in the same d

I am Lyosha [343]

Answer:

$2.09\ \text{m/s}$

$22298.4\ \text{J}$

Explanation:

m = Mass of each the cars = $1.6\times 10^4\ \text{kg}$

$u_1$ = Initial velocity of first car = 3.46 m/s

$u_2$ = Initial velocity of the other two cars = 1.4 m/s

v = Velocity of combined mass

As the momentum is conserved in the system we have

$mu_1+2mu_2=3mv\\\Rightarrow v=\dfrac{u_1+2u_2}{3}\\\Rightarrow v=\dfrac{3.46+2\times 1.4}{3}\\\Rightarrow v=2.09\ \text{m/s}$

Speed of the three coupled cars after the collision is $2.09\ \text{m/s}$ .

As energy in the system is conserved we have

$K=\dfrac{1}{2}mu_1^2+\dfrac{1}{2}2mu_2^2-\dfrac{1}{2}3mv^2\\\Rightarrow K=\dfrac{1}{2}\times 1.6\times 10^4\times 3.46^2+\dfrac{1}{2}\times 2\times 1.6\times 10^4\times 1.4^2-\dfrac{1}{2}\times 3\times 1.6\times 10^4\times 2.09^2\\\Rightarrow K=22298.4\ \text{J}$