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4 years ago

Where is the distribution of positive charges found in the atom?

Physics

1 answer:

Agata [3.3K]4 years ago

4 0

I think the answer is proton

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A 80.0-kg airplane pilot pulls out of a dive by following, at a constant speed of 180km/hr, the arc of a circle whose radius is

wolverine [178]

Answer: 8.33m/s²

Explanation:

Mass of the airplane pilot = 80kg

The speed of plane v = 180km/h = 50m/s

The radius of circle r = 300 m

The acceleration of the plane will be calculated as:

a = v²/r

a = 50²/300

a = 2500/300

a = 8.33m/s²

Note that 180km/h was converted to m/s by

= (180 × 1000)/(60 × 60)

= 180000/3600

= 50m/s

1000 meters = 1 kilometer

60 minutes = 1 hour

60 seconds = 1 minute

3600 seconds = 1 hour

6 0

3 years ago

What is the acceleration of a 32-kg object is a 6.75-N force is being applied to it?

zimovet [89]

<span>0.21 m/s2

A.)

hope this helps best of luck :)
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6 0

3 years ago

Two long, straight wires are parallel and 10 cm apart.One carries a current of 2.0 A, the other a current of 5.0A. (a) If the tw

lubasha [3.4K]

Answer:

Explanation:

Given

Distance between two wires $d=10 cm$

Current value $i_1=2 A$

$i_2=5 A$

(a)If current flows in opposite direction

When current Flows in opposite direction the two wires will repel each other

Force due to current carrying wire $F=\frac{\mu _0i_1i_2}{2\pi r}$

$F_{12}=F_{21}=\frac{\mu _0\times 2\times 5}{2\times \pi \times 0.1}$

$F_{12}=\frac{4\pi \times 10^{-7}\times 2\times 5}{2\pi \times 0.1}$

$F_{12}=2\times 10^{-5} N$ (Repulsive Force)

(b)If current is flowing in the same direction

When direction of current is same then force will be attractive in nature

$F_{12}=F_{21}=\frac{\mu _0i_1i_2}{2\pi r}$

$F_{12}=\frac{4\pi \times 10^{-7}\times 2\times 5}{2\pi \times 0.1}$

$F_{12}=2\times 10^{-5} N$ (attractive Force)

5 0

4 years ago

A certain car is capable of accelerating at a uniform rate of 0.85 m/s^2. What is the magnitude of the car's displacement as it

gogolik [260]

Solution: 85.11 m

Given:

acceleration of the car, $a= 0.85 m/s^{2}$

initial velocity, $u=83km/h=23.05 m/s$

final velocity, $v=94 km/h=26.11 m/s$

we need to find the displacement (s) of the car.

we would use the equation of motion:

$2as=v^{2}-u^{2}\\
\Rightarrow s=\frac{v^{2}-u^{2}}{2a} \\
\Rightarrow s=\frac{26.11^{2}-23.05^{2}}{2\times0.85}\\
\Rightarrow s=85.11 m$

hence, the displacement done by the car is = 85.11 m

7 0

3 years ago

Can someone please help me ASAP?

Wittaler [7]

Answer:

Explanation:

8 0

3 years ago

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