21. Which polysaccharide is the most abundant on the planet, gives structure to plants, can be digested by

The diagram below represents a change in guard cells that open and close pores in a plant) This Change directly helps to A. incr

AveGali [126]

The correct answer is option C, that is, regulate water loss.

Guard cells refer to the cells enclosing each stomata. They assist in monitoring the rate of transpiration by closing and opening the stomata. The guard cells possess the tendency to monitor the closing and opening of stomata by changing shape. The shape of the guard cells modifies on the basis of the concentration of potassium ions and water found in the cells themselves.

The stomatal pores get closed when carbon dioxide is no longer needed for the process of photosynthesis. The guard cells swell when movement of water takes place inside these pores, and thus, the opening of stomatal pores occurs, and as water moves out, the guard cell closes. Thus, guard cells play an essential role in regulating water loss.

5 0

3 years ago

Name three bright ring features, and explain why they are so bright.

murzikaleks [220]

The F Ring, the Cassini Division, and the C Ring are bright ring features. They are bright due to the low concentration of materials within them, which allows sunlight to shine through.

7 0

3 years ago

Read 2 more answers

The factor favoring filtrate formation at the glomerulus is the ________.

mina [271]

The glomerulus hydrostatic pressure.

4 0

3 years ago

What blood condition is caused by iron deficiency?

Dmitry [639]

Answer is Anemia, which is the absence of a good portion of red blood cells.

5 0

3 years ago

Dihybrid crosses can be used to predict two independent alleles in the future generation. In echidnas, the allele for brown fur

Mrac [35]

Answer:

25% of the offsprings will be BBCC

Explanation:

This is a typical dihybrid cross involving two distinct genes. One coding for fur colour and the other for claw sharpness. The allele for brown fur (B) is dominant over the allele for black fur (b) in the first gene while the allele for sharp claws (C) is dominant over the allele for dull claws (c) in the second gene.

In a cross between parents with genotypes: BbCc x BBCC , each parent will produce four possible allelic combinations of gametes as follows:

BbCc: BC, Bc, bC, bc

BBCC: BC, BC, BC, BC

Using these gametes in a punnet square (see attached image), 16 possible offsprings will be produced with four distinct genotypes:

BBCC (4)

BBCc (4)

BbCC (4)

BbCc (4)

According to the question, an offspring that is homozygous dominant for both traits will possess a genotype: BBCC

N.B: Homozygous dominant means contains same alleles for the dominant trait.

Hence, offsprings with genotype, BBCC, from this cross are expected to be 4 out of the 16 possible offsprings. Hence, the percentage is 4/16 × 100 = 25%.

8 0

3 years ago