Which is the mRNA made during transcription of the following DNA template?

2 answers:

5 0

A. -C-G-A-A-U-C-A-G-G-U-A-A

RNA has three of the same bases as DNA and the fourth is U (uracil) instead of T (thymine)
C pairs with G, G pairs with C
A pairs with U, T(U) pairs with A

mestny [16]4 years ago

4 0

The mRNA made during transcription of G-C-T-T-A-G-T-C-C-A-T-T DNA template results in C-G-A-A-U-C-A-G-G-U-A-A

Further Explanation:

The double-helical structure of a DNA is duplicated through a process called DNA replication. Then the DNA undergoes a process of transcription and form RNA. After this, the RNA processing starts with post translation modification and forms rRNA, tRNA, AND mRNA. These RNA goes into the last stage called translation. Then, the formation of protein occurs.

The nucleic acid is mainly composed of small nucleotides. Every nucleotide is comprised of deoxyribose, nitrogenous base, and phosphate group. DNA is made up of four distinct type of nitrogenous base:

Cytosine
Adenine
Guanine
Thymine

Also, the RNA comprised adenine, cytosine and guanine, but they don’t have thymine. They consists uracil as a substitute of thymine. The adenine base in DNA paired with thymine but in RNA adenine paired with uracil. The cytosine is paired with the guanine base. So, the sequence of mRNA is GCTTAGTCCAT forms the template sequence CGAAUGGUAA in mRNA.

Learn more:

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Answer Details:

Grade: High School

Subject: Molecular Biology

Chapter: Gene expression

Keywords:

DNA, RNA, concept map, replication, double helical, nucleotides, transcription, proteins, translation, mRNA, rRNA, tRNA, cytosine, adenine, uracil, thymine.

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