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elixir [45]
3 years ago
14

What is one trillion to the tenth power?

Mathematics
1 answer:
Mamont248 [21]3 years ago
3 0

Answer:

1e+120

Step-by-step explanation:

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Jonah finds the length of the sides of the quadrilateral
azamat

Answer: Side BC has a length of square root 10 units

Step-by-step explanation: I just took the test

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4 years ago
Evaluate the expression for s=4 and t=8
Andru [333]
Whats the expression so you can plug those numbers in.
4 0
3 years ago
Read 2 more answers
Find the area of the composite figure.
Minchanka [31]

Answer:

132 square feet

Step-by-step explanation:

The formula for the area of a triangle is 1/2 * b * h. B stands for base and h stands for height. 1/2 multiplied by the base, 10, is 5. We then multiply 5 by 12 which is 60. Let's look at the rectangle now. The area of a rectangle is length by width. The length is 12ft and the width is 6ft. 12 * 6 = 72. 72+60=132 square feet.

8 0
3 years ago
Work out the volume of the solid shape<br><br> Give your answers in terms of pi please
kirill [66]

*The complete question is in the picture attached below.

Answer:

756πcm³

Step-by-step Explanation:

The volume of the solid shape = volume of cone + volume of the hemisphere.

==> 270πcm³ + ½(4/3*π*r³)

To calculate the volume of the hemisphere, we need to get the radius of the hemisphere = the radius of the cone.

Since volume of cone = 270πcm³, we can find r using the formula for the volume of cone.

==> Volume of cone = ⅓πr²h

⅓*π*r²*10 = 270π

⅓*10*r²(π) = 270 (π)

10/3 * r² = 270

r² = 270 * ³/10

r² = 81

r = √81

r = 9 cm

Thus, volume of hemisphere = ½(4/3*π*r³)

==> Volume of hemisphere = ½(⁴/3 * π * 9³)

= ½(972π)

Volume of hemisphere = 486πcm³

Volume of the solid shape

= volume of cone + volume of the hemisphere.

==> 270πcm³ + 486πcm³

= 756πcm³

3 0
3 years ago
You coach a basketball ball team of 12 players; 5 players must be on the floor at all times; Figuring that every player can play
makvit [3.9K]
The function "choose k from n", nCk, is defined as
  nCk = n!/(k!*(n-k)!) . . . . . where "!" indicates the factorial

a) No position sensitivity.
The number of possibilities is the number of ways you can choose 5 players from a roster of 12.
  12C5 = 12*11*10*9*8/(5*4*3*2*1) = 792
You can put 792 different teams on the floor.

b) 1 of 2 centers, 2 of 5 guards, 2 of 5 forwards.
The number of possibilities is the product of the number of ways, for each position, you can choose the required number of players from those capable of playing the position.
  (2C1)*(5C2)*(5C2) = 2*10*10 = 200
You can put 200 different teams on the floor.
4 0
3 years ago
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