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Tpy6a [65]
3 years ago
5

Given f(x)=2x^2-3x+1, determine the value of 3f(-2x)

Mathematics
1 answer:
krok68 [10]3 years ago
4 0

Answer:

Step-by-step explanation:

3f(-2x)= 3[2(-2x)^2-3(-2x)+1]

         =3[2(4x^2)+6x+1]

         =3[8x^2+6x+1]

         =24x^2+18x+3

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