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nlexa [21]
3 years ago
14

Which statement correctly explains how Andre could find the solution to the following system of linear equations using eliminati

on?Multiply the first equation by –7 and the second equation by 8, and then subtract.Multiply the first equation by -7 and the second equation by 8, and then add.Multiply the first equation by 2 and the second equation by 9, and then add.Multiply the first equation by –2 and the second equation by 9, and then subtract.Which statement correctly explains how Andre could find the solution to the following system of linear equations using elimination?Multiply the first equation by –7 and the second equation by 8, and then subtract.Multiply the first equation by -7 and the second equation by 8, and then add.Multiply the first equation by 2 and the second equation by 9, and then add.Multiply the first equation by –2 and the second equation by 9, and then subtract.
Mathematics
1 answer:
grin007 [14]3 years ago
7 0

umm ,this is too long could you maybe putt it in smaller form so I can answer

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Which table shows a proportional relationship between x and y?
oksano4ka [1.4K]
The top one. Think about the difference between each one: X goes from 1 to 2 and Y goes from 5 to 10. Each number you go up, Y increases by 5. This means there is a proportional relationship.
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5. Simplify the expression and find its value when p= 4 and q = -5:
Ierofanga [76]
  • <u>Answer</u>: -180

Step-by-step explanation:

\bf   \blue{ \boxed{  \bf p = 4 \:  \: and \:  \: q =  - 5 \Rightarrow pq = 4 \times ( - 5) =  - 20}}

3(p2q + pq2 - pq) - 6pq + 3pq2 =

3[-20 × 2 + (-20) × 2 - (-20)] - 6 × (-20) + 3 × 2 × (-20) =

3[-40 + (-40) + 20] - 6 × (-20) + 3 × 2 × (-20) =

3(-40 - 40 + 20) - 6 × (-20) + 3 × 2 × (-20) =

3(-80 + 20) - 6 × (-20) + 3 × 2 × (-20) =

3 × (-60) - 6 × (-20) + 3 × 2 × (-20) =

-180 + 120 + 6 × (-20) =

-180 + 120 + (-120) =

-180 + 120 - 120 =

-60 - 120 = -180

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2 years ago
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Find the values of k so that each remainder is three. <br> 10. (x^2+ 5x + 7) = (x + k)
Goryan [66]

Answer:

k=1\text{ or } k=4

Step-by-step explanation:

We can use the Polynomial Remainder Theorem. It states that if we divide a polynomial P(x) by a <em>binomial</em> in the form (x - a), then our remainder will be P(a).

We are dividing:

(x^2+5x+7)\div(x+k)

So, a polynomial by a binomial factor.

Our factor is (x + k) or (x - (-k)). Using the form (x - a), our a = -k.

We want our remainder to be 3. So, P(a)=P(-k)=3.

Therefore:

(-k)^2+5(-k)+7=3

Simplify:

k^2-5k+7=3

Solve for <em>k</em>. Subtract 3 from both sides:

k^2-5k+4=0

Factor:

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Zero Product Property:

k-1=0\text{ or } k-4=0

Solve:

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So, either of the two expressions:

(x^2+5x+7)\div(x+1)\text{ or } (x^2+5x+7)\div(x+4)

Will yield 3 as the remainder.

5 0
3 years ago
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