3 years ago

What is the length of AB? Please help so I can graduate thanks!!

Mathematics

1 answer:

4vir4ik [10]3 years ago

5 0

HOPE it helps!!!!!!!!

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Rewrite the function by completing the square (vertex form)<br><br> f(x)=x^2+16x-46

insens350 [35]

Answer:

$\large\boxed{f(x)=(x+8)^2-110}$

Step-by-step explanation:

$\text{The vertex form of equation}\ y=ax^2+bx+c:\\\\y=a(x-h)^2+k\\\\\text{We have the equation:}\\f(x)=x^2+16x-46=x^2+2(x)(8)-46=x^2+2(x)(8)+8^2-8^2-46\\\\\text{use}\ (a+b)^2=a^2+2ab+b^2\to x^2+2(x)(8)+8^2=(x+8)^2\\\\f(x)=(x+8)^2-64-46=(x+8)^2-110$

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2 years ago

What is the length of the line segment whose endpoints are (1, 1) and (3, - 3)

Shtirlitz [24]

Answer:

length= √[ (a-c)^2 + (b-d)^2 ]

Step-by-step explanation:

5 0

2 years ago

Do number 4 please DONT get it wrong or i block report, i really need help please :)

andriy [413]

Area of the figure = 30.28 m²

Solution:

The given image is splitted into two shapes.

One is rectangle and the other is semi-circle.

Length of the rectangle = 6 m

Width of the rectangle = 4 m

Area of the rectangle = length × width

= 6 m × 4 m

= 24 m²

Area of the rectangle = 24 m²

Diameter of the semi-circle = 4 m

Radius of the semi-circle = 4 m ÷ 2 = 2 m

Area of the semi-circle = $\frac{1}{2} \ \pi r^2$

$$=\frac{1}{2} \times 3 .14 \times 2^2$

$=6.28$

Area of the semi-circle = 6.28 m²

Area of the figure = Area of the rectangle + Area of the semi-circle

= 24 m² + 6.28 m²

= 30.28 m²

Area of the figure = 30.28 m²

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3 years ago

15 POINTS WILL MARK BRAINLIEST!!!!! Choose the group responsible for the Declaration of Independence.

Bess [88]

Answer: second Congress

Step-by-step explanation:

Short and sweet

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3 years ago

10.125 as a fraction

zubka84 [21]

Answer:

$\frac{81}{8}$

Step-by-step explanation:

$10.125=\frac{10125^{(125}}{1000}=\frac{81}{8}$

6 0

3 years ago

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