Answer:
if that statement is true, then DE=ST, and ST=4 so your answer should be <u>DE=4</u>
Explanation:
you can tell that they are even from looking at the first statement, it states <u>DE</u>F=<u>ST</u>U, emphasizing on the DE=ST part, it gives your the answer right there because ST=4
The slope is 4 because you go up 4 and over one which created the slope 4/1 which is just 4
Answer:
And is an inclusive conjunction, meaning more can follow and exist at the same time, while or is an exclusive conjunction, meaning only one choice can exist at one time.
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given that the television show Degenerate Housewives has been successful for many years. That show recently had a share of 18, meaning that among the TV sets in use, 18% were tuned to Degenerate Housewives.
Each household is independent of the other and there two outcomes.
X no of households that are tuned to Degenerate Housewives. is Bin (12, 0.18)
the probability that none of the households are tuned to Degenerate Housewives. P(none) =_______0.0924_____
the probability that at least one household is tuned to Degenerate Housewives. P(at least one) = ____1-0.0924 = 0.9076______
the probability that at most one household is tuned to Degenerate Housewives. P(at most one) = _____0.3359______
If at most one household is tuned to Degenerate Housewives, does it appear that the 18% share value is wrong? (Hint: Is the occurrence of at most one household tuned to Degenerate Housewives unusual?)
No 33% is not unusual.
a = amount deposited at 3.5%
b = amount deposited at 4.5%
we know that "b" is twice as much as "a", thus b = 2a.
![\begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{3.5\% of a}}{\left( \cfrac{3.5}{100} \right)a}\implies 0.035a \\\\[-0.35em] ~\dotfill\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{4.5\% of 2a}}{\left( \cfrac{4.5}{100} \right)2a}\implies 0.045(2a)](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7B%7Cc%7Cll%7D%20%5Ccline%7B1-1%7D%20%5Ctextit%7Ba%5C%25%20of%20b%7D%5C%5C%20%5Ccline%7B1-1%7D%20%5C%5C%20%5Cleft%28%20%5Ccfrac%7Ba%7D%7B100%7D%20%5Cright%29%5Ccdot%20b%20%5C%5C%5C%5C%20%5Ccline%7B1-1%7D%20%5Cend%7Barray%7D~%5Chspace%7B5em%7D%5Cstackrel%7B%5Ctextit%7B3.5%5C%25%20of%20a%7D%7D%7B%5Cleft%28%20%5Ccfrac%7B3.5%7D%7B100%7D%20%5Cright%29a%7D%5Cimplies%200.035a%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cbegin%7Barray%7D%7B%7Cc%7Cll%7D%20%5Ccline%7B1-1%7D%20%5Ctextit%7Ba%5C%25%20of%20b%7D%5C%5C%20%5Ccline%7B1-1%7D%20%5C%5C%20%5Cleft%28%20%5Ccfrac%7Ba%7D%7B100%7D%20%5Cright%29%5Ccdot%20b%20%5C%5C%5C%5C%20%5Ccline%7B1-1%7D%20%5Cend%7Barray%7D~%5Chspace%7B5em%7D%5Cstackrel%7B%5Ctextit%7B4.5%5C%25%20of%202a%7D%7D%7B%5Cleft%28%20%5Ccfrac%7B4.5%7D%7B100%7D%20%5Cright%292a%7D%5Cimplies%200.045%282a%29)
we also know that whatever "a" amount is, their sum is 2250, thus
