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exis [7]
3 years ago
14

NEED HELP FAST !! Does anyone know what element this is ??

Chemistry
1 answer:
bonufazy [111]3 years ago
5 0

Answer:

Carbon

Carbon atoms have 6 protons.

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Will mark brainliest. Anyone willing to do this?
Norma-Jean [14]

Answer:

ACTIVITY 1

Sample 1 has a stronger taste of lemon, and is more sour.

Sample 2 has a sweeter taste, my guess is because there's more sugar:lemon juice ratio.

7 0
3 years ago
The reaction between sulfur dioxide and oxygen is reversible.
RUDIKE [14]

Explanation:

the correct answer is

D) 0.636 mol/dm³

3 0
2 years ago
Name the compound formed when a copper cation has a 2+ charge combined with a bromine anion that has a 1- charge.
Rashid [163]

Answer: The compound is called copper (II) bromide or cupric bromide

Explanation:

7 0
2 years ago
g For the following reaction, 0.500 moles of silver nitrate are mixed with 0.285 moles of copper(II) chloride. What is the formu
scZoUnD [109]

Answer:

CuCl_2 is the formula for the limiting reagent.

Mass of silver chloride produced is 71.8 g.

Explanation:

CuCl_2+2AgNO_3\rightarrow 2AgCl+Cu(NO_3)_2

Moles of silver nitrate = 0.500 mol

Moles of copper(II) chloride = 0.285 mol

According to reaction, 2 moles of silver nitrate reacts with 1 mole of copper chloride , then 0.500 mole of silver nitrate will react with :

\frac{1}{2}\times 0.500 mol=0.250 mol of copper(II) chloride

As we can see that moles of copper(II) chloride will be reacting is 0.250 mol less than present moles of copper (II) chloride ,so this means that silver nitrate is limiting reagent.

And moles of silver chloride to be formed will depend upon silver nitrate.

According to reaction, 2 moles of silver nitrate gives 2 moles of silver chloride , then 0.500 mole of silver nitrate will give  :

\frac{2}{2}\times 0.500 mol=0.500 mol of silver chloride

Mass of silver chloride produced:

0.500 mol × 143.5 g/mol = 71.8 g

7 0
3 years ago
The ksp value for lead(ii chloride is 2.4 × 10?4. what is the molar solubility of lead(ii chloride?
charle [14.2K]
Molar solubility is number of moles of the solute that can be dissolved per liter of solution before the solution becomes saturated. 

The molar solubility of lead(ii) chloride with ksp value of 2.4 × 10e4 can be solve as: 

Ksp = s2 = 2.4 × 10e4
s2 = 2.4 × 10e4
s = √(2.4 × 10e4)
s =  154.9 mol/L
6 0
3 years ago
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