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2 years ago

How many grams are in 0.35 moles of C2H6?

Chemistry

1 answer:

dmitriy555 [2]2 years ago

6 0

Answer:

10.524163999999896

Explanation:

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Two containers, one with a volume of 3.0 L and the other with a volume of 2.0 L contain, respectively, argon gas at 1.1 atm and

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a. $p_T=0.93atm$ .

$p_{Ar}=0.66atm\\\\p_{He}=0.3atm$

$x_{Ar}=0.6875\\\\x_{He}=0.3125$

Explanation:

Hello,

In this case, considering that the valve is opened, we can use the Boyle's law in order to compute the final pressure of argon by considering its initial pressure and volume and a final volume of 5.0 L:

$p_{Ar}=\frac{1.1atm*3.0L}{5.0L}=0.66atm$

And the final pressure of helium:

$p_{He}=\frac{0.75atm*2.0L}{5.0L}=0.3atm$

Which actually are the partial pressure of both of them, it means that the total pressure is:

Finally, the mole fraction of each gas is computed by considering the Dalton's law:

$x_i=\frac{p_i}{p_T}$

$x_{Ar}=\frac{0.66atm}{0.93atm} =0.6875\\\\x_{He}=\frac{0.3atm}{0.93atm} =0.3125$

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How many grams are in 0.35 moles of C2H6?​

How many grams are in 0.35 moles of C2H6?