Answer:
m = 190. g MgCl2
Explanation:
Use a molar ratio to get the # of moles MgCl2 produced from 4.00 mol of HCl:
4.00 mol HCl × (1 mol MgCl2/2 mol HCl) = 2.00 mil MgCl2
So 2.00 moles of MgCl2 will be produced. To find the mass in grams, use the molar mass of MgCl2:
2.00 mol MgCl2 × (95.211 g MgCl2/1 mol MgCl2)
= 190. g MgCl2
Explanation:
1 ) first u have to balance the equation but in this case it is already balanced.
2) checking for the limiting reactant:
13 mol O2 × (1mol H2O / 1mol of O2) = 13 mol of H2O
14 mol of ethanol × (1mol H2O/ 1molof ethanol) = 14 mol of H2O
the less amount of moles produced from the O2 so the limiting reactant is oxygen
3) calculating the products moles
13 mol O2 × (1mol H2O / 1mol of O2) = 13 mol
13 mol O2 × (1mol Ch3Cooh / 1mol O2) = 13 mol
note: the ratios obtained from the balanced equation
4) the excess reagent is the ethanol 1 mol will be remain
Answer:
what do you need help with i cant see it
Explanation:
Each mole of a substance contains 6.02 x 10²³ particles
Atoms of Fe = 4.5 x 6.02 x 10²³
= 2.709 x 10²⁹ atoms
Answer:
B. it is a community of plants,animals and there physical surrounding.
