What is the mole ratio of iron (III) chloride (FeCl3) to zinc chloride (ZnCl2) ?

While ethanol (CH3CH2OH) is produced naturally by fermentation, e.g. in beer- and wine-making, industrially it is synthesized by

grin007 [14]

Answer:

$n_{C2H_5OH}^{eq}=14.234mol$

Explanation:

Hello,

In this case, the reaction is:

$C_2H_4+H_2O\rightleftharpoons CH_3CH_2OH$

Thus, the law of mass action turns out:

$Kc=\frac{[CH_3CH_2OH]_{eq}}{[H_2O]_{eq}[CH_2CH_2]_{eq}}$

Thus, since at the beginning there are 29 moles of ethylene and once the equilibrium is reached, there are 16 moles of ethylene, the change $x$ result:

$[CH_2CH_2]_{eq}=29mol-x=16mol\\x=29-16=13mol$

In such a way, the equilibrium constant is then:

$Kc=\frac{\frac{x}{V} }{\frac{16mol}{V}* \frac{3mol}{V}} =\frac{\frac{13mol}{75.0L} }{\frac{16mol}{75.0L}* \frac{3mol}{75.0L}} =20.31$

Thereby, the initial moles for the second equilibrium are modified as shown on the denominator in the modified law of mass action by considering the added 15 moles of ethylene:

$Kc=\frac{\frac{13+x_2}{V} }{\frac{16+15-x_2}{V}* \frac{3-x_2}{V}} =20.31$

Thus, the second change, $x_2$ finally result (solving by solver or quadratic equation):

$x_2=1.234mol$

Finally, such second change equals the moles of ethanol after equilibrium based on the stoichiometry:

$n_{C2H_5OH}^{eq}=x+x_2=13mol+1.234mol\\n_{C2H_5OH}^{eq}=14.234mol$

Best regards.

5 0

3 years ago

when 824 J of heat is added to 9 grams of oil at 30°c , the temperature increases to 87°C. what is the specific heat of the oil

sattari [20]

Answer:

c = 1.61 j/g.°C

Explanation:

Given data:

Mass of oil = 9 g

Heat added = 824 j

Initial temperature = 30°C

Final temperature = 87°C

Specific heat of oil = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = Final temperature - final temperature

ΔT = 87°C - 30°C

ΔT = 57 °C

Q = m.c. ΔT

824 j = 9 g × c × 57 °C

824 j = 513 g. °C × c

c = 1.61 j/g.°C

5 0

3 years ago

Investigating a fire scene, Investigator Smith determines several places where fires started. What might this indicate about the

grigory [225]

Answer:

an accelerant was used because maybe some was spilt and therefore leaving a smell and evidence

3 0

2 years ago

It takes 46 ml of 0.124 m koh to neutralize 28.1 ml of h2so4 solution. what is the concentration of the h2so4 solution? answer i

julia-pushkina [17]

The balanced equation of for the above reaction is as follows;
2KOH + H₂SO₄ ---> K₂SO₄ + 2H₂O
stoichiometry of KOH to H₂SO₄ is 2:1
the number of KOH moles reacted - 0.124 mol/L x 0.046 L = 0.0057 mol
for complete neutralisation the base should react with acid in 2:1 molar ratio
if 2 mol of KOH reacts with 1 mol of H₂SO₄
then 0.0057 mol of KOH reacts with - 1/2 x 0.0057 mol = 0.0029 mol
the number of H₂SO₄ moles in 28.1 mL - 0.0029 mol
Molarity is number of H₂SO₄ moles in 1 L
therefore number of H₂SO₄ moles in 1 L - 0.0029 mol / 0.0281 L = 0.103 M
molarity of H₂SO₄ is 0.103 mol/L

6 0

2 years ago

Acid chlorides can be converted into primary amines with the loss of a single carbon atom via the Curtius rearrangement. The rea

Marat540 [252]

Answer:

Find the given attachment.

5 0

2 years ago