Can someone help with this and give me an explanation on how u get im struggling

Dominik [7]

Answer: you can use take out the 5 and multiply 5 by 120=600.then take out the 6 and multiply 6 by 120=720.then take 600 and 720,put it into a fraction.

6 0

3 years ago

The probability of getting heads is 1/2. Predict how many times you would get heads if you flipped the dime 200 times.

Rudik [331]

If the probability of getting heads is 1/2 and you flipped a coin 200 times you would land on heads 100 times

6 0

2 years ago

Read 2 more answers

The ammunition storage room has 10 feet between the floor and the ceiling. Each box of ammunition is 10 feet tall. Each crate of

KIM [24]

Answer:

the maximum number of crates that can be stacked between the floor and ceiling

$\frac{height \hspace{0.1cm} of \hspace{0.1cm} ammunition \hspace{0.1cm} box}{height \hspace{0.1cm} of \hspace{0.1cm} each \hspace{0.1cm} crate} = \frac{10 \hspace{0.1cm} feet}{12 \hspace{0.1cm} inches} = \frac{10 \times 12 \hspace{0.1cm} inches }{12 \hspace{0.1cm} inches} = 10 \hspace{0.1cm} crates$

where 1 foot = 12 inches. SO the answer is that a maximum of 10 crates can be stacked from floor to ceiling.

Step-by-step explanation:

i) the maximum number of crates that can be stacked between the floor and ceiling

$\frac{height \hspace{0.1cm} of \hspace{0.1cm} ammunition \hspace{0.1cm} box}{height \hspace{0.1cm} of \hspace{0.1cm} each \hspace{0.1cm} crate} = \frac{10 \hspace{0.1cm} feet}{12 \hspace{0.1cm} inches} = \frac{10 \times 12 \hspace{0.1cm} inches }{12 \hspace{0.1cm} inches} = 10 \hspace{0.1cm} crates$

where 1 foot = 12 inches

3 0

2 years ago

2ab + a^3 +5a^2b^2 - 2b^3<br> Need help i have to write this in standard form

german

2ab + a^3 + 5a^2b^2 - 2b^3
= a^3 - 2b^3 + 2ab + 5a^2b^2 (this is the expression in standard form)

4 0

2 years ago

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What is the product of x+2 and x-7? Write your answer in standard form.

Leto [7]

X^2-5x-14
It is the correct answer I think

5 0

3 years ago