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2 years ago

Determine whether the graph of y^5=x^3 is symmetric with respect to the Y axis the x-axis or the origin.

Mathematics

1 answer:

zhannawk [14.2K]2 years ago

7 0

9514 1404 393

Answer:

the origin

Step-by-step explanation:

Both terms are of odd degree, so the function is an odd function. It is symmetrical with respect to the origin.

If you recast this as y = f(x), then ...

f(x) = x^(3/5)

When we look at f(-x), we find ...

f(-x) = ((-x)^3)^(1/5) = -(x^3)^(1/5) = -(x^(3/5)) = -f(x)

An odd root of a number has the same sign as the number.

When f(-x) = -f(x), the function is odd and symmetrical about the origin.

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1.11(5) - 11(4) =

Natali5045456 [20]

Answer:

1) 11

2) -8

3) 30

15) 80x - 128

16) 138y

Step-by-step explanation:

For these problems, you will need to use either PEMDAS or distributive property.

PEMDAS stands for parentheses, exponents, multiplication/division, addition/subtraction. Problems must be solved by going in order of the acronym, always starting with anything in parentheses first.

Example of PEMDAS:

2) 8(-3 + 2)

Solve for what's inside the parentheses first. There are no exponents, multiplication, or division within the parentheses so next would be addition and subtraction.

-3 + 2 = -1 so the problem will now look like:

8 (-1)

Next, PEMDAS says to look for exponents. There are none. Multiplication and division are next. 8 is being multiplied by -1 so lets try that:

8 × -1 = -8

-8

Distributive property is when you take the number being multiplied on the outside of the parentheses and multiply it to each individual number within the parentheses.

Example of distributive property:

2) 8(-3 + 2)

Multiply the number on the outside of the parentheses, 8, to each number within the parentheses, -3 and 2:

8 × -3 and 8 × 2

The problem should look like:

-24 + 16

Then solve:

-8

Use whichever method you are most comfortable with as both will produce the same answer. I will solve the first few and the last few to help you.

11(5) - 11(4)

55 - 44

6(9) - 4(6)

54 - 24

15) *You must use distributive property for these last problems as you cannot add or subtract numbers and variables*

16(5x - 8)

80x - 128

*You can only combine like terms so this is fully simplified*

16)

23y(2 + 4)

46y + 92y

138y

5 0

2 years ago

Charles and Seth are building a ramp for Sasha and Samantha. The base of the triangle is 11ft and it's height is 5ft. How long i

Arlecino [84]

Answer: 12.1 ft

Step-by-step explanation:

A ramp represents a right-angled triangle so Pythagorean formula can be used to find the diagonal length which will also be the hypotenuse.

c² = a² + b²

Where:

c = hypotenuse

a = base

b = Height

c² = 11² + 5²

c² = 121 + 25

c² = 146

c = √146

c = 12.1 ft

5 0

3 years ago

If Jane invests $1500 in a savings account with a 6% interest rate compounded monthly, how long will it take until Jane’s amount

Viefleur [7K]

Answer:

22 months it take at all..

6 0

2 years ago

Dom has enough tins of paint to cover a total surface of 280m.

Inessa [10]

So he has to paint 255 m from the 280 m of paint he has
First divide 255/280 to give you a decimal
You should get .9107
Since this is in decimal form (out of 1) you want to get percentage which is out of 100 you multiply by 100
So .9107 times 100
This gives you the percentage which is
91.07%
Now it says round to 1 decimal so it would be
91.1%

3 0

2 years ago

Mark the statement either true (in all cases) or false (for at least one example). If false, construct a specific example to sho

LUCKY_DIMON [66]

Answer with Step-by-step explanation:

We are given that $v_1,v_2,..,v_4$ are in $R^4$ and $v_1,v_2,v_3$ is linearly dependent then {v_1,v_2,v_3,v_4}[/tex] is also linearly dependent.

We have to find that given statement is true or false.

Dependent vectors:Dependent vectors are those vectors in which atleast one vector is a linear combination of other given vectors.

Or If we have vectors $x_1,x_2,....x_n$

Then their linear combination

$a_1x_1+a_2x_2+.....+a_nx_n=0$

There exist at least one scalar which is not zero.

If $v_1,v_2,v_3$ are dependent vectors then

$a_1v_1+a_2v_2+a_3v_3=0$ for scalars $a_1,a_2,a_3$

Then , by definition of dependent vectors

There exist a vector which is not equal to zero

If vector $v_3$ is a linear combination of $v_1\;and \;v_2$ , So at least one of vectors in the set is a linear combination of others and the set is linearly dependent.

Hence, by definition of dependent vectors

{ $v_1,v_2,v_3,v_4$ } is linearly dependent.

Option B is true.

8 0

3 years ago