Answer:
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the starting point of the function is 0
Answer:
The equation of the tangent line passing through the point (-2,3) is
4 x + y +5 =0
Step-by-step explanation:
<u><em>Step(i):-</em></u>
<em>Given that the slope of the tangent</em>
<em> </em>
<em></em>
<em> m = -2( 3-1) = -4</em>
<em>Given point x = -2</em>
<em> y = f(-2) =3</em>
<em>∴The given point ( x₁ , y₁) = ( -2 ,3)</em>
<u><em>Step(ii):-</em></u>
The equation of the tangent line passing through the point (-2,3)


y -3 = -4( x+2)
y-3 = -4x -8
4x + y -3+8=0
4x +y +5=0
<u><em>Step(iii):-</em></u>
<em>The equation of the tangent line passing through the point (-2,3) is</em>
<em> 4 x + y +5 =0</em>
<em></em>
<span>( 9 + 2 i ) ( 3 − 5 i ) − ( 9 + i ) ( 3 − 5 i )
FOIL
i x i = -1
(27 + 6i - 45i +10) - (27 +3i - 45i +5)
Combine like terms and distribute the negative
37 - 39i + 42i - 32
3i + 5
This is the farthest I could go with it. Assuming you were looking for a simplification though you did not specify your desired answer's criteria. Hope this helped!</span>