In what occupations is self-employment common?

Step by step 7 ,9, and 11 please. EVEN IF U CANT DO ALL, u can help with 1 or 2. Ill mark brainly.

gregori [183]

Answer:

7) $4 \ log_3(x) - 4 \ log_3(y)$

9) $5log_4(7) - 5log_4(12)$

11) $5log_5 \ (x) - log_5 \ (y)$

Step-by-step explanation:

$log_3 (\frac{x}{y})^{4}$

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Use Logarithm of a Quotient which states

$log_b \frac{M}{N} = log_b M-log_bN$

And also use Logarithm of a Power which states

$log_b\ M^{n} = n\log_bM$

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So using these two properties,

7. $4 \ log_3(x) - 4 \ log_3(y)$

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For #9, use the same logarithm propertied

$log_4(\frac{7}{12})^5 = 5log_4(7) - 5log_4(12)$

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#11 is also the same concept

$log_5\ \frac{x^5}{y} = 5log_5 \ (x) - log_5 \ (y)$

It is not - 5 log5(y) since only x is to the power of 5 not y

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Hope this is what you were looking for and helps you! Have a nice day/night :)

5 0

3 years ago

In the Salk vaccine field trial, 400,000 children were part of a randomized controlled double-blind experiment. Just about half

EastWind [94]

Answer:

Step-by-step explanation:

From the given information:

The number of children that were randomly allocated to each vaccination group; n₁ = 200,000

No of polio cases X₁ = 57

Now, in the vaccine group:

the proportion of polio cases is:

$\hat p_1 = \dfrac{57}{200000}$

= 0.000285

The number of children that were randomly allocated to the placebo group, n₂ = 200,000

No of polio cases X₂ = 142

In the placebo group

the proportion of polio cases is:

$\hat p_2 = \dfrac{142}{200000}$

Null and alternative hypothesis is computed as follows:

H₀: There is no difference in the proportions of polio cases between both groups.

H₁: There is a difference in the proportions of polio cases between both groups.

Let assume that the level of significance ∝ = 0.05

The test statistic can be computed as:

$Z = \dfrac{\hat p_1-\hat p_2}{\sqrt{\dfrac{\hat p_1 \hat q_1}{n_1}+ \dfrac{\hat p_2 \hat q_2}{n_2}}}$

$Z = \dfrac{0.000285-0.000710}{\sqrt{\dfrac{0.000285(1-0.000285)}{200000}+ \dfrac{0.000710(1-0.000710)}{200000}}}$

$Z = \dfrac{-4.25\times 10^{-4}}{\sqrt{\dfrac{0.000285(0.999715)}{200000}+ \dfrac{0.000710(0.99929)}{200000}}}$

Z = - 6.03

P-value = 2P(Z < -6.03)

From the Z - tables

P-value = 2 × 0.0000

= 0.000

We reject the H₀ provided that P-value is very less.

Therefore, we may conclude that there is a difference in the proportions of polio cases between the vaccine group and placebo group not due to chance.

7 0

3 years ago

A local hamburger shop sold a combined total of hamburgers and cheeseburgers on Thursday. There were fewer cheeseburgers sold th

myrzilka [38]

Answer:

the number of hamburgers sold on Thursday were 325.

Step-by-step explanation:

The total number of hamburger and cheese burger is missing

i will replace it with any figure, you can replace it wit your given data and you will get the solution.

A local hamburger shop sold a combined total of 593 hamburgers and cheeseburgers on Thursday

There were 57 fewer cheeseburgers sold than hamburgers

How many hamburgers were sold on thursday

Let h be the number of hamburgers and c be the number of cheeseburgers.

Using this information we can set up two equation as:

$h+c=593\\c=h-57$

Now we need to solve these two equations to get the value of number of hamburgers. For that we use substitution method as shown below:

$h+h-57=593\\2h-57=593\\2h=650\\h=325$

Therefore, the number of hamburgers sold on Thursday were 325.

6 0

3 years ago

In the given diagram, find the values of x, y, and z.

anyanavicka [17]

Answer:

B) x=64, y=21, z=64

Step-by-step explanation:

X=180-116=64

Y cannot equal 115, and one angle is already 95, and that would put it over 180. The only remaining choice for y=21

z=180-95-21=64

5 0

3 years ago

Can someone please help me

Ilya [14]

I believe it is -81k^2

-27k^3-81k^2-81k-27

6 0

3 years ago