Solve log (x - 2) is he got to lock 27 (4x+27)

Consider this system of equations.

Leona [35]

-x=6, x intercept is at x=-6 or (-6,0)
3y=6, y intercept is at y=2 or (0,2)

5 0

3 years ago

Read 2 more answers

What is the domain of this function?

Montano1993 [528]

That would be 1 =< x < infinity.

That is the last option.

6 0

4 years ago

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The lifetime of a certain type of battery is normally distributed with mean value 15 hours and standard deviation 1 hour. There

KIM [24]

Answer:

If the lifetime of batteries in the packet is 40.83 hours or more then, it exceeds for 5% of all packages.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 15

Standard Deviation, σ = 1

Sample size = 4

Total lifetime of 4 batteries = 40 hours

We are given that the distribution of lifetime is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

Standard error due to sampling:

$\displaystyle\frac{\sigma}{\sqrt{n}} = \frac{1}{\sqrt4} = 0.5$

We have to find the value of x such that the probability is 0.05

P(X > x) = 0.05

$P( X > x) = P( z > \displaystyle\frac{x - 40}{0.5})=0.05$

$= 1 -P( z \leq \displaystyle\frac{x - 40}{0.5})=0.05$

$=P( z \leq \displaystyle\frac{x - 40}{0.5})=0.95$

Calculation the value from standard normal z table, we have,

$\displaystyle\frac{x - 40}{0.5} = 1.64\\x = 40.825 \approx 40.83$

Hence, if the lifetime of batteries in the packet is 40.83 hours or more then, it exceeds for 5% of all packages.

8 0

4 years ago

If f(x)=2x^2−3x+1 and g(x)=x+5, what is f(g(x))?

Alex_Xolod [135]

If $f(x)=2x^{2}-3x+1,$ then

$f(g(x))=2[g(x)]^{2}-3g(x)+1\\ \\ f(g(x))=2(x+5)^{2}-3(x+5)+1\\ \\ f(g(x))=2(x^{2}+10x+25)-3(x+5)+1\\ \\ f(g(x))=2x^{2}+20x+50-3x-15+1\\ \\ f(g(x))=2x^{2}+20x-3x+50-15+1\\ \\ \boxed{\begin{array}{c}f(g(x))=2x^{2}+17x+36 \end{array}}$

7 0

4 years ago

A cereal manufacturer is concerned that the boxes of cereal not be under filled or overfilled. Each box of cereal is supposed to

Vaselesa [24]

Answer:

We conclude that the population average weight of a cereal box is equal to 13 ounces.

Step-by-step explanation:

We are given that a cereal manufacturer is concerned that the boxes of cereal not be under filled or overfilled.

A random sample of 36 boxes is tested. The sample average weight is 12.85 ounces and the sample standard deviation is 0.75 ounces.

Let $\mu$ = population average weight of a cereal box

So, Null Hypothesis, $H_0$ : $\mu$ = 13 ounces {means that the population average weight of a cereal box is equal to 13 ounces}

Alternate Hypothesis, $H_A$ : $\mu$ $\neq$ 13 ounces {means that the population average weight of a cereal box differs from 13 ounces}

The test statistics that will be used here is One-sample t test statistics as we don't know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample average weight = 12.85 ounces

$\sigma$ = sample standard deviation = 0.75 ounces

n = sample of boxes = 36

So, test statistics = $\frac{12.85-13}{\frac{0.75}{\sqrt{36} } }$ ~ $t_3_5$

= -1.20

The value of the test statistics is -1.20.

Since, in the question we are not given with the level of significance so we assume it to be 5%. Now at 5% significance level, the t table gives critical values between -2.03 and 2.03 at 35 degree of freedom for two-tailed test.

Since our test statistics lies within the range of critical values of t, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the population average weight of a cereal box is equal to 13 ounces.

3 0

3 years ago

Solve log (x - 2) is he got to lock 27 (4x+27)​

Solve log (x - 2) is he got to lock 27 (4x+27)