<h3>
Answer: 6</h3>
Mark the locations -6 and 0 on the number line. Note that going from -6 to 0, or vice versa, will take exactly 6 steps. Put another way, the distance between 0 and -6 is 6 units. Absolute value represents distance, so it is never negative.
We say 
Effectively, all we're doing is removing the negative sign.
The coordinates of the pre-image of point F' is (-2, 4)
<h3>How to determine the coordinates of the pre-image of point F'?</h3>
On the given graph, the location of point F' is given as:
F' = (4, -2)
The rule of reflection is given as
Reflection across line y = x
Mathematically, this is represented as
(x, y) = (y, x)
So, we have
F = (-2, 4)
Hence, the coordinates of the pre-image of point F' is (-2, 4)
Read more about transformation at:
brainly.com/question/4289712
#SPJ1
Answer:
Step-by-step explanation:
You need to change the denominator into a the least common denominator, 4 and 3 both have 12 in common. 12 is your new denominator but what you to the bottom you must do to the top. So when you multiply 3/4 by 3/3 you will get 9/12.
Then you want to make 4 1/3 into a improper fraction, which would be 13/3 you want to multiply this by 4 and you will get 52/12. You will then add 52/12 to 9/12 and get 61/12 or 5 1/12.
If you need any more help please let me know.
Substitute y=4x to the second equation:
x^2 + (4x)^2 = 17
x^2 + 16x^2 = 17
17x^2 = 17
x^2 = 17/17
x^2 = 1
x = 1 and -1
When x=1, y=4(1) = 4
When x=-1, y=4(-1) = -4
Thus the solutions would be (1,4) and (-1,-4). That would correspond to D. and A.
Answer:
Use math papa the calculator and copy and paste your work into it or use inspect if your on computer
Step-by-step explanation:
