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marysya [2.9K]
3 years ago
11

100 POINTS Write an inequality of the form Ax + B ≤ C to represent the word problem using your answers for A, B, and C. Solve th

e inequality and show your work.
Mathematics
1 answer:
Yakvenalex [24]3 years ago
8 0

Answer:

5x +3y>-15

5(0)+3(0)

0+0=   0 > -15

Step by step explanation

We have to create a scenario that leads to an inequality of the form ax + b > c.

<em> </em>

<em>Word problem: A family went to an park. Entry fee of the park for a family is $20 and the cost of a ride is $10 per person. The family spent more than $100 on that ride. </em>

The required inequality is

Subtract 20 from both sides.

Divide both sides by 10.

It means the number of rides must be greater than 8.

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natta225 [31]

Answer:

(4y^{6})^{3}-(10z^{2})^{3}

Step-by-step explanation:

we have

64y^{18}-1000z^{6}

we know that

64=4^{3}

y^{18}=(y^{6})^{3}

1000=10^{3}

z^{6}=(z^{2})^{3}

Substitute the values in the expression

(4^{3})((y^{6})^{3})-(10^{3})((z^{2})^{3})

(4y^{6})^{3}-(10z^{2})^{3}

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Answer:

0.015 km/s

Step-by-step explanation:

40 km/hr

0.015 km/s

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Solve each equation by completing the square <br> 6) m² + 16m – 8 = 0
Natali5045456 [20]

Answer:

m = - 8 ± 6\sqrt{2}

Step-by-step explanation:

Given

m² + 16m - 8 = 0 ( add 8 to both sides )

m² + 16m = 8

To complete the square

add ( half the coefficient of the m- term )² to both sides

m² + 2(8)m + 64 = 8 + 64

(m + 8)² = 72 ( take the square root of both sides )

m + 8 = ± \sqrt{72} = ± \sqrt{36(2)} = ± 6\sqrt{2}

Subtract 8 from both sides

m = - 8 ± 6\sqrt{2}

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a square dance set requires 4 couples 8 dancers with each couple standing on one side of a square. There are 250 people at a squ
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Given:

1 set requires 4 couples 8 dancers.

Total number of people at a square dance = 250.

To find:

The greatest number of sets possible at the dance.

Solution:

We have,

Total people = 250

1 set = 8 people.

\text{Number of possible sets}=\dfrac{\text{Total people}}{\text{People required for 1 set}}

\text{Number of possible sets}=\dfrac{250}{8}

\text{Number of possible sets}=31.25

Number of possible sets cannot be a decimal or fraction value. So, approx. the value to the preceding integer.

\text{Number of possible sets}\approx 31

Therefore, the number of possible sets at the dance is 31.

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An athlete runs every day for one week. The following week she runs one mile further than she ran on that day the previous week.
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